Y=mx+b
Find the y-intercept (-2,1)
1=-1\2(-2)+b
1=2\2+b
1=1+b
-1+1=b
0=b
Y=-1\2x this the answer ,the slope is zero you don't need to write it!
If events A and B are independent,
For mutually exclusive then p(A or B) = p(A) + p(B).
For not mutually exclusive then p(A or B) = p(A) + p(B) - p(A and B)
And: p(A and B) = p(A) * p(B)
Given: <span>p(A) = 0.22 and p(B) = 0.24.
</span>
<span>∴ p(A and B) = p(A) * p(B) = 0.22*0.24 = 0.0528
</span>
If A and B are mutually exclusive
∴ p(A or B) = p(A) + p(B) = 0.22 + 0.24 = 0.46
If A and B are not mutually exclusive
∴ p(A or B) = p(A) + p(B) - p(A and B) = 0.22 + 0.24 - <span>0.0528 = 0.4072
</span>
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note: Two events are mutually exclusive if it is not possible for both of them to occur, which mean the occurrence of one event "excludes" the possibility of the other event.
Answer:
The vertex for the function f(x) = 3(x – 2)2 + 4 is at (2, 4).
Step-by-step explanation:
Find the vertex for f(x) = 3 (x - 2)^2 + 4
f(x) = 3 (x - 2)^2 + 4 can also be written as:
y = 3 (x - 2)^2 + 4
To find critical points, first compute f'(x):
d/(dx)(3 (x - 2)^2 + 4) = 6 (x - 2):
f'(x) = 6 (x - 2)
Solve 6 (x - 2) = 0
6x - 12 = 0
6x = 12
x = 2
iI you substitute x = 2 in 3 (x - 2)^2 + 4 then you get:
y = 3 (x - 2)^2 + 4
x = 2
y = 3 (2 - 2)^2 + 4
y = 3 (0)^2 + 4
y = 3 (0) + 4
y = 4
Answer: The vertex for the function f(x) = 3(x – 2)2 + 4 is at ( 2, 4 ).
Answer:
<em><u>2/10 and 3/10</u></em>
Step-by-step explanation:
Hello!
The best way of finding common denominators is using their factors!
(of denominators)
10 : 1, 2, 5, 10
2 : 1, 2
We also can see that 10 is divisible by 2.
For that reason, 1/2 is equivalent to 2 * 10 ÷ 2.
That's 10.
So <em>5/10 and 3/10</em> have a common denominator 10.
Hope this helps!
