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Vsevolod [243]
3 years ago
6

If an ancient campfire were analyzed, was found to have only about one-eighth the carbon-14 that is normally found in living thi

ngs, how long ago was that campfire extinguished? Answer in units of y.
Physics
1 answer:
devlian [24]3 years ago
5 0

Answer:

17047.54 years or 17048 y

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2=half-life of the carbon-14 =5670 years

t= time elapsed

Ao= activity of living C-14

A= activity if the sample under study

But A= 1/8 Ao

Hence;

0.693/5670= 2.303/t log(Ao/1/8Ao)

1.22×10^-4 = 2.303/t log 8

1.22×10^-4 = 2.0798/t

t= 2.0798/1.22×10^-4

t= 17047.54 years

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Answer:

25 atoms

Explanation:

7 0
3 years ago
A car is stopped at a red light. When the light turns green, it accelerates up
Marat540 [252]

Answer:

a = 2.5 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} =v_{o} +a*t

where:

Vf = final velocity = 25 [m/s]

Vo = initial velocity = 0 (star from the rest)

a = acceleration [m/s²]

t = time = 10 [s]

25 = 0 + (a*10)

a = 25/10

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6 0
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two-point charges are 10.0 cm apart and have charges of 2.0 uc and -2.0uc respectively What is the magnitude of the electrical f
Scorpion4ik [409]

Answer:

Electric field due to two charges is given as

E = 1.44 \times 10^7 N/C

Explanation:

As we know that two charges are opposite in nature

So the electric field at the mid point of two charges will add together

so the net field is given as

E = 2\frac{kq}{r^2}

now we have

q = 2\times 10^{-6} C

r = 5 cm = 0.05 m

now we have

E = 2\frac{(9\times 10^9)(2\times 10^{-6})}{0.05^2}

E = 1.44 \times 10^7 N/C

6 0
3 years ago
The rate at which correct flows is measured in _?
Reika [66]

C. amperes

this what i think it is

6 0
3 years ago
When a particle of mass m is at (x comma 0 )​, it is attracted toward the origin with a force whose magnitude is StartFraction y
Dahasolnce [82]

Answer:

W = y (b-a) / ab

Explanation:

Work is defined by the expression

W = ∫ F. dr

In this case the force is in the same direction of displacement, so the scalar product is reduced to the ordinary product

W = ∫ F dr

The expression of the strength left is

F = -y / x²

let's replace and integrate

W = ∫ (-y / x²) dx

W = -y (-1 / x)

We evaluate between the lower limit x = b + a to the upper limit x = 0 + a

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8 0
3 years ago
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