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podryga [215]
3 years ago
7

Robbie leaves his house and drives 5 miles North to the post office, 8 miles East to the park, 5 miles South to the grocery stor

e, and then 8 miles West to get back home. What is Robbie's displacement?
Physics
1 answer:
Anika [276]3 years ago
7 0

Answer:

Robbie's displacement is zero.

Explanation:

Displacement is called the change in position that a body experiences, from an initial point A, to an end point B, through movement. That is, displacement is understood as the length and direction that a body travels to move from an initial point to an end point. Displacement is a vector type quantity, which is described from the magnitude and the direction.

Only the start point and the end point are important for displacement. When the object ends at the same starting point, the displacement will be zero.

You know that Robbie leaves his house and drives 5 miles North to the post office, 8 miles East to the park, 5 miles South to the grocery store, and then 8 miles West to get back home.

<u><em>Since in this case the start point and end point is Robbie's house, then the offset will be zero.</em></u>

<u><em></em></u>

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A 10 kg farm wagon is sitting at the top of a hill that makes a 370 angle with the horizontal when the brake suddenly fails. The
yanalaym [24]

Answer:

F = 1475.75 N      

Explanation:

Given:-

- The mass of the wagon m = 10 kg

- The slope angle θ = 37°

- The initial velocity of wagon at top of hill, vi = 0 m/s

- The amount of distance it plows into haystack, s2 = 2.0 m

-The wagon rolls down the slope for distance, s1 = 50 m

Find:-

Determine The force the haystack exerts on the wagon?

Solution:-

- First we must note that the wagon rolls down the slope with a constant acceleration due to gravity ( g ) component acting down the slope. The acceleration ( a ) of the wagon can be given as:

                       a = g*sin ( θ ).

- Since, the acceleration of the cart is constant we can apply third kinematic equation of motion with initial velocity at top of hill vi = 0 m/s and the velocity " v1 " right before it plows into the haystack at the bottom of hill after traveling a distance of s1 = 50 meters.

                       v1^2 = vi^2 + 2*a*s1  

                       v1^2 = 0 + 2*g*sin ( θ )*s1  

                       v1^2 = 2*9.81*sin ( 37 )*50    

                       v1 = √590.381

                       v1 = 24.30 m/s

- The constant force exerted by the haystack ( F ) as the wagon plows the haystack with a velocity "v1" by a distance of s2 and comes to, final velocity vf = 0, a stop.

Apply principle of work-done energy:

- Where, work is done on the wagon by haystack for W = F*s2.

                    W = Δ K.E        

                    W = 0.5*m* ( vf^2 - v1^2 )

                    F*s2 = 0.5*m*( v1 )^2

                    F = 0.5*m*( v1 )^2 / s2

                    F = 0.5*10*590.30 / 2    

                    F = 1475.75 N          

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Answer:

According to Newton's third law

Explanation:

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how could you increase the gravitational potential energy of an object without changing its mass and gravity​
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Please see the answer

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Help on this physics question
fredd [130]

By using the equations for <em>parabolic</em> motion, we proceed to present the answers for the paragraph seen in the picture: a) t ≈ 0.553 s, b) s = 2.212 m, c) s = 11.060 m.

<h3>How to analyze a system on parabolic motion</h3>

A system is on <em>parabolic</em> motion if such system can be represented as a particle, that is, a system whose geometry is negligible, and its motion is a combination of <em>horizontal</em> movement at <em>constant</em> velocity and <em>vertical</em> <em>uniformly accelerated</em> movement due to gravity and all <em>viscous</em> and <em>rotational</em> effects are negligible.

The time required for the droplet to reach the ground is:

1.5 m = (1 / 2) · (9.807 m / s²) · t²

t = √[2 · (1.5 m) / (9.807 m / s²)]

t ≈ 0.553 s

And the <em>horizontal</em> distance traveled by the droplet is:

s = (4 m / s) · (0.553 s)

s = 2.212 m

Now, we apply the same procedure for the case of sneezing person:

1.5 m = (1 / 2) · (9.807 m / s²) · t²

t = √[2 · (1.5 m) / (9.807 m / s²)]

t ≈ 0.553 s

s = (20 m / s) · (0.553 s)

s = 11.060 m

To learn more on parabolic motion: brainly.com/question/16992646

#SPJ1

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