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Amanda [17]
3 years ago
7

8. A jaguar runs 4200 meters at the speed of 400 meters per minute. How

Physics
1 answer:
ollegr [7]3 years ago
7 0

Answer:

10.5min

Explanation:

Given parameters:

Distance  = 4200m

Speed  = 400m/min

Unknown:

Time taken for this run  = ?

Solution:

Speed is the distance divided by the time taken.

   Speed  = \frac{distance }{time }  

  Time  = \frac{distance}{speed }  

 Now insert the parameters and solve;

 Time  = \frac{4200}{400}   = 10.5min

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If the voltage impressed across a circuit is held constant while the resistance doubles, what change occurs in the current?
bazaltina [42]

Answer:

The current halves

Explanation:

The relationship between voltage, current and resistance in a circuit is given by Ohm's law:

V=RI

where

V is the voltage

R is the resistance

I is the current

We can rewrite the formula as

I=\frac{V}{R}

we see that I is directly proportional to V and inversely proportional to R.  In this problem, V is held constant while R is doubled:

R'=2R

so, the new current in the circuit will be

I'=\frac{V}{R'}=\frac{V}{2R}=\frac{1}{2}I

So, the current halves.

4 0
4 years ago
If the radius of an object in circular motion is doubled, what change will occur in the centripetal force?
cestrela7 [59]

Answer:

The centripetal force will be 1/2 as big as it was. (option c)

Explanation:

Recall that centripetal force (F_c) is defined as: F_c=m\,* \frac{v^2}{r} where "v" is the tangential velocity of the object in circular motion, "r" is the radius of rotation and "m" is the object's mass.

So if we start with such formula with a given mass, radius, and tangential velocity, and then we move to a situation where everything stays the same except for the radius which doubles, then the new centripetal force (F'_c) will be given by: F'_c=m\,* \frac{v^2}{2r}

and this is half (1/2) of the original force:

F'_c=m\,* \frac{v^2}{2r}\\F'_c=m\,* \frac{v^2}{r}*\frac{1}{2} \\F'_c=F_c\,*\,\frac{1}{2}

which is expressed by option "c" of the provided list.

8 0
3 years ago
Read 2 more answers
A billiard ball with a mass of 0.15 kg has a velocity of 5 m/s. It strikes the bumper of the table perpendicularly and bounces s
Marianna [84]
Initial momentum = 0.15 kg * (-5 m/s) = - 0.75 N*s

final momentum = 0.15 * ( 3 m/s) =  0.45 N*s

Change in momentum = final momentum - initial momentun =

= 0.45N*s - (- 0.75N*s) =  1.2 N*s

Answer:  1.2 N*s


5 0
3 years ago
A block with mass ma = 14.0 kg on a smooth horizontal surface is connected by a thin cord that passes over a pulley to a second
Drupady [299]
<span>We can assume that the horizontal surface has no friction and the pulley is massless. We can use Newton's second law to set up an equation. F = Ma F is the net force M is the total mass of the system a is the acceleration a = F / M a = (mb)(g) / (ma + mb) a = (6.0 kg)(9.80 m/s^2) / (6.0 kg + 14.0 kg) a = 58.8 N / 20 kg a = 2.94 m/s^2 The magnitude of the acceleration of the system is 2.94 m/s^2</span>
7 0
4 years ago
How much power can I generate while lifting a mass for 30 seconds?
zepelin [54]

about 5 watts (5W) of power

8 0
4 years ago
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