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defon
2 years ago
7

PLZZZ HELP!!! 80PTS!!!

Physics
1 answer:
vodka [1.7K]2 years ago
4 0

Answer:

Impulse = 206.28 * 10 = 2062.8 g.m/s

Explanation:

Impulse is equal to the product of force and time

Here

Density of car =  0.54  g/mL

Volume of car = 38.2 mL

Mass of the car is equal to the product of density and volume of car

Mass of the car = 0.54 * 38.2 = 20.628 grams

Acceleration of the car is 10 m/s^2

Force is equal to product of mass and acceleration

F = 20.628 * 10 = 206.28 g .m/s^2

Impulse = F * t

Impulse = 206.28 * 10 = 2062.8 g.m/s

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2 years ago
Not in book
umka2103 [35]

Answer:

x=2.4365\ m

and

x=-1.4365\ m

Explanation:

Given:

  • first charge, q_1=5\times 10^{-3}\ C
  • second charge, q_2=3\times 10^{-3}\ C
  • position of first charge, x_1=-2\ m
  • position of second charge, x_2=-1\ m

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

E_1=E_2

  • since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}

\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}

3(r^2+1+2r)=5r^2

2r^2-6r-3=0

r=3.4365 \&\ r=-0.4365

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

x=-1+3.4365=2.4365\ m

and

x=-1-0.4365=-1.4365\ m

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