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Semenov [28]
3 years ago
11

What I'd the equation of a line that passes through points (-2,6) and (4,-3)?

Mathematics
1 answer:
Blababa [14]3 years ago
4 0

slope = (y2-y1)/(x2-x1)

 m = (-3-6)/(4--2)

  = -9/6

=-3/2

y -y1 = m(x-x1)

y-6 =-3/2 (x--2)

y-6 =-3/2 (x+2)

y-6  =-3/2 x -3

add 6

y = -3/2 x +3

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