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3 years ago

What I'd the equation of a line that passes through points (-2,6) and (4,-3)?

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

slope = (y2-y1)/(x2-x1)

m = (-3-6)/(4--2)

= -9/6

=-3/2

y -y1 = m(x-x1)

y-6 =-3/2 (x--2)

y-6 =-3/2 (x+2)

y-6 =-3/2 x -3

add 6

y = -3/2 x +3

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Find the value of x .just put the equation as the answer plz

Inessa [10]

Answer:

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minus 42 from both sides and solve for x,

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3 years ago

5th grade math. Correct answer will be marked brainliest

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Step-by-step explanation:

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3 years ago

The system of equations 2y=14-2x and y=-x+7 is graphed. What is the solution to the system of equations?

9966 [12]

Answer: Infinitely many solutions

Step-by-step explanation:

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3 years ago

the frame of a picture is 28 cm by 32 cm outside and is of uniform width.What is the width of the frame if 192 cm2 of the pictur

natita [175]

Answer:

The width of the frame is equal to $8\ cm$

Step-by-step explanation:

Let

x-------> the width of the frame picture

we know that

$(28-2x)(32-2x)=192$

$896-56x-64x+4x^{2} =192$

$4x^{2}-120x+704=0$

Simplify

$x^{2}-30x+176=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-30x+176=0$

$a=1\\b=-30\\c=176$

substitute in the formula

$x=\frac{30(+/-)\sqrt{(-30)^{2}-4(1)(176)}} {2(1)}$

$x=\frac{30(+/-)\sqrt{196}} {2}$

$x=\frac{30(+/-)14} {2}$

$x=\frac{30+14} {2}=22\ cm$ ----> this solution is not logic

$x=\frac{30-14} {2}=8\ cm$

The width of the frame is equal to $8\ cm$

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4 years ago

10∙20=8∙d210•20=8•d2 .

tekilochka [14]

Is that the whole equation? Exactly from the book or paper?

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3 years ago