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2 years ago

What I'd the equation of a line that passes through points (-2,6) and (4,-3)?

Mathematics

1 answer:

Blababa [14]2 years ago

4 0

slope = (y2-y1)/(x2-x1)

m = (-3-6)/(4--2)

= -9/6

=-3/2

y -y1 = m(x-x1)

y-6 =-3/2 (x--2)

y-6 =-3/2 (x+2)

y-6 =-3/2 x -3

add 6

y = -3/2 x +3

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