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FrozenT [24]
4 years ago
12

Help!!! ASAP!! :3 Will Givve BRAINLIEST!!

Mathematics
1 answer:
Norma-Jean [14]4 years ago
8 0

Answer:

V = 672 cm³ (Option 3)

Step-by-step explanation:

Volume of Rectangular Prism = Length * Width * Height

<u><em>Where L = 14 cm, W = 6 cm and H = 8 cm</em></u>

V = 14 * 6 * 8

V = 672 cm³

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V<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%20%2A%202%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="\frac{3}{4} * 2
myrzilka [38]

Answer:

1\frac{3}{4}

Step-by-step explanation:

In order to find the answer, you first need to convert the mixed number (2 1/3) into a improper fraction and then multiply.

\frac{3}{4} \times2\frac{1}{3}

2\frac{1}{3} =3\times2=6+1=7=\frac{7}{3}

\frac{3}{4} \times\frac{7}{3}

3\times7=21

4\times3=12

=\frac{21}{12} =\frac{7}{4} =1\frac{3}{4}

=1\frac{3}{4}

Hope this helps.

7 0
3 years ago
What is the degree of x4 - 3x + 2?
sukhopar [10]

Answer:

4

Step-by-step explanation:

Since the highest power of x is 4 in this case.

8 0
3 years ago
What is the domain of the following function represented by ordered pairs?
Nastasia [14]

Answer:

{-6, -2, 3, 4} is the domain of the following functions

5 0
2 years ago
Hey guys I have a hard time with these questions. Can someone explain it to me? :)
frutty [35]
The slope would be 0

This is basically how you do it if you need more help let me know

6 0
3 years ago
Read 2 more answers
Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0   is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

                 =  x² + x(-r - s) +  rs

or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

⇒  b +  s = - r

or, s  = -r - b

Now, given : r = Rational  and the negative of a rational is also rational.

⇒  -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0   is also rational number.

7 0
4 years ago
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