Answer:
Step-by-step explanation:
The mean SAT score is 
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it 
) is
Next they draw a random sample of n=70 students, and they got a mean score (denoted by 
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form
and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.
<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
Answer:
see below
Step-by-step explanation:
The area of a circle is given by
A = pi r^2 where r is the radius
A = pi (6.5)^2
A =42.25 pi
If we approximate pi by 3.14
A = 42.25 * 3.14 =132.665
If we use the pi button
A = 132.7322896
B is the correct answer R=Q-7s/4
Top:
x / (x + 1) - 1 / x
= [x^2 - (x +1)] / x(x+1)
= (x^2 - x - 1 ) / x (x+1)
Bottom:
x / (x + 1) + 1 / x
= [x^2 + (x +1)] / x(x+1)
= (x^2 + x + 1 ) / x (x+1)
Now you have:
(x^2 - x - 1 ) / x (x+1)
----------------------------
(x^2 + x + 1 ) / x (x+1)
= (x^2 - x - 1 ) / x (x+1) * x (x+1) / (x^2 + x + 1 )
= (x^2 - x - 1 ) /(x^2 + x + 1 )
Answer:
x^2 - x - 1
---------------------
x^2 + x + 1
Answer:
D. 22,417 feet
Step-by-step explanation:
Fine the diagram in the attachment for proper elucidation. Using the SOH, CAH, TOA trigonometry identity to solve for the distance (x) from the plane (P) to the observer (O), the longest side x is the hypotenuse and the side facing the angle of elevation is the opposite.
Hypotenuse = x and Opposite = 15,000feet
According to SOH;
Hence the distance (x) from the plane P to the observer O is approximately 22,417 feet
