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PIT_PIT [208]
3 years ago
5

24.94 I 29% of what number

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0

86. 

.29n=24.94

divide both sides by .29

answer is 86

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What is the value of x ? Enter your answer in the box
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If the mass of a material is 45 grams and the volume of the material is 11 cm^3, what would the density of the material be?
Nuetrik [128]

Answer:

Density of material would be 4.09 g/cm^3

units is g/cm^3

Step-by-step explanation:

Given: The mass of a material is 45 grams and the volume of the material is 11 cubic centimeter

Density is defined as mass per unit volume.

It is given by:

p= \frac{m}{V} where p is the density , m is the mass and V is the volume of the material respectively.

Here, Density is expressed in grams per centimeter cubed (g/cubic cm)

Here, m = 45 g , V = 11 cubic cm

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therefore, density of a material would be, 4.09 g/cm^3

and its units is g/cm^3

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3 years ago
How to graph an exponential function
irina1246 [14]

Step-by-step explanation:

Exponential function is given by general form y=ab^x

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say a=1 and b=2 then we can write function as :

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or y=2^x

To graph this or any exponential function, we just need to find some points then join them by a curved line.

Like plug x=0, 1, 2,... into above function and find points:

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Find more points similarly then graph them to get the graph as shown below:


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A certain test preparation course is designed to help students improve their scores on the USMLE exam. A mock exam is given at t
e-lub [12.9K]

Answer:

17.67-2.92\frac{2.517}{\sqrt{3}}=13.427    

17.67+2.92\frac{2.517}{\sqrt{3}}=21.913    

So on this case the 90% confidence interval would be given by (13.427;21.913)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=17.67

The sample deviation calculated s=2.517

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=3-1=2

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,2)".And we see that t_{\alpha/2}=2.92

Now we have everything in order to replace into formula (1):

17.67-2.92\frac{2.517}{\sqrt{3}}=13.427    

17.67+2.92\frac{2.517}{\sqrt{3}}=21.913    

So on this case the 90% confidence interval would be given by (13.427;21.913)    

6 0
3 years ago
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