All categories

3 years ago

Please help me find the Measure of the arc!!

Mathematics

1 answer:

noname [10]3 years ago

3 0

124 is the answer....

You might be interested in

Which of the following has the larger area?

kari74 [83]

A rectangle by 170 square inches. :)

6 0

3 years ago

Read 2 more answers

Select one of the factors of 4x^2 + 5x − 6

BARSIC [14]

Answer:

The answer to your question is: letter C

Step-by-step explanation:

4x² + 5x - 6

Process

4 x - 6 = - 24

Find two numbers that added gives + 5 and multiply gives -24

These numbers are + 8 and - 3

4x² + 8x - 3x - 6

4x ( x + 2) - 3(x + 2)

(x + 2) (4x - 3)

5 0

4 years ago

Read 2 more answers

PLZZZZZZZZZZZZZZZZZZZZZZ HELP!<br><br> -3x+4=-2 show your work!!!

Katyanochek1 [597]

Answer:

x=2

Step-by-step explanation:

5 0

3 years ago

Two hundred copies can be made for $6.00.<br>What is the unit rate?

Mekhanik [1.2K]

Answer:

.03 cents

Step-by-step explanation:

6 divided by 200 equals 0.03

5 0

3 years ago

Read 2 more answers

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

3 years ago