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3 years ago

5

what is the area of an isosceles trapezoid, if the lengths of its bases are 16cm and 30cm and the diagonals are perpendicular to

each other?

1 answer:

noname [10]3 years ago

3 0

I think 161.... if its a 45 45 90

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Planes A and B intersect.

viktelen [127]

Answer:

Point W

Step-by-step explanation:

Planes A and B intersect at an angle. Intersection of lines is when two lines meets at a particular point and cuts each other at the same point. Its a measure of perpendicularity for right angles and greater or lesser for others.

At any point W, line m and line n cuts each other at point W to form an angle as shown from the diagram.

6 0

2 years ago

Read 2 more answers

A motor boat travels 60 miles down a river in three hours but takes five hours to return upstream. Find the rate of the boat in

Kryger [21]

Answer:

boat: 16 mph
current: 4 mph

Step-by-step explanation:

speed = distance / time

The rate downriver is (60 mi)/(3 h) = 20 mi/h.

The rate upriver is (60 mi)/(5 h) = 12 mi/h.

The rate of the boat in still water is the average of these:

(20 +12)/2 mi/h = 16 mi/h

The rate of the current is the difference between the boat speed and actual speed:

16 mi/h - 12 mi/h = 4 mi/h

3 0

3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

I NEED HELP ON THIS!!!!!

seropon [69]

#1 pipers pepperoni pieces- $0.41
noras nummy nuggets- $0.34
noras nummy nuggets is better
#2 +65?

8 0

2 years ago

James has read 1/8 of a book eric has read 1/3 of the same book what fraction more of the book has eric read than james

BARSIC [14]

1/3 = 8/24

1/8 = 3/24

use 24 since it's the LCM of 8 and 3

8-3/24 = 5/24

3 0

3 years ago