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3 years ago

5

what is the area of an isosceles trapezoid, if the lengths of its bases are 16cm and 30cm and the diagonals are perpendicular to

each other?

1 answer:

noname [10]3 years ago

3 0

I think 161.... if its a 45 45 90

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In AUVW, the measure of ZW=90°, VU = 65, UW = 33, and

Viefleur [7K]

Answer: 56/33

Step-by-step explanation:

7 0

3 years ago

What is the perimeter of a square if it has an area of 36 square centimeters?

kirill115 [55]

Let x is the side of the square
so A = x * x or A = x^2 = 36
As you know 36 is a perfect square root = 6^2
Then x = 6 cm

Perimeter = 4x = 4(6) = 24 cm

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3 years ago

2.789 in expanded form

FromTheMoon [43]

It is...........

2.789=2 ones and 7 tenths 8 hundreths 9 thousandths

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3 years ago

What is the probability of rolling a 6 and then a 7 on a number cube?

Kazeer [188]

Answer:

0%, there is no chance you can roll a 7 on a number cube with 6 sides.

If you meant a 5 and then a 6, or 2 rolls subsequently, it would be 1/36.

Step-by-step explanation:

1/6*1/6=1/36

6 0

3 years ago

Determine if x - 2 is a factor of p(x) = x4 - 3x2 + 2x - 8, and explain why.

Natali [406]

<u>Answer:</u>

If x-2 is a factor of p(x) = x^{4} - 3 x^{2} + 2 x - 8 ,then p(x) = 0

<u>Solution:</u>

According to factor theorem of polynomials,

x-a is a factor of polynomial p(x), if and only p(a)=0

<u>Step 1:</u>

Since x-2 is factor of p(x),

x - 2 = 0

x = 2

<u>Step 2:</u>

$p(x) = x^{4} - 3 x^{2} + 2 x - 8 ------ (equation 1)$

By substituting x = 2 in equation 1,

$p(x) = 2^{4} - 3(2)^{2} + 2(2) - 8$

p(x) = 16 - 3(4 ) + 4 -8

p(x) = 16 - 12 - 4

p(x) = 16 - 16

p(x) = 0

Since x - 2 is a factor of p(x) , we get p(x)=0

7 0

3 years ago