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Sauron [17]
3 years ago
14

A recursive rule for a geometric sequence is a1=4/9;an=3an−1

Mathematics
2 answers:
Rudik [331]3 years ago
5 0
The answer is (4/9)(3)^n-1
Mrac [35]3 years ago
3 0

Answer:

Explicit rule for this sequence is, a_n = 49\cdot (3)^{n-1}

Step-by-step explanation:

A recursive rule for a geometric sequence is a_1=49, a_n = 3a_{n-1}

First term a_1= 49

To get second term, just multiply the first term by 3

a_n = 3 a_{n-1}

a_2 = 3 a_1

a_2= 3\cdot 49

so, we get the common ratio r = 3

Now, Explicit rule for geometric sequence is given by:

a_n = a_1 \cdot (r)^{n-1}

Here, a_1= 49 and r= 3

So, explicit rule is :

a_n = 49\cdot (3)^{n-1}

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Find the equation of a line that contains the points (−3,−1) and (−4,−7). Write the equation in slope-intercept form
BARSIC [14]

Answer:

y =6x+17

Step-by-step explanation:

First we need to find the slope

m = (y2-y1)/(x2-x1)

   = (-7- -1)/(-4 - -3)

   = (-7+1)/(-4+3)

   -6/-1

   6

The slope intercept form of the equation is

y = mx+b  where m is the slope and b is the y intercept

y = 6x+b

Substitute a point into the equation

-1 = 6(-3) +b

-1 = -18+b

Add 18 to each side

17 =b

The equation is

y =6x+17

8 0
3 years ago
What's the answer of 13846+8273636-3763x8273736
ipn [44]
13846+8273636
= 8287482

8287482-3763
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7 0
3 years ago
Center (-15,11) radius 2
kodGreya [7K]

Answer:

(x+15)^2+(y-11)^2=4

Step-by-step explanation:

<u><em>The question is</em></u>

How do you write an equation for a circle with center (-15,11) and radius 2?

we know that

The equation of a circle in center radius form is given by

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center of the circle

r is the radius of the circle

substitute the given vales

(x+15)^2+(y-11)^2=2^2

(x+15)^2+(y-11)^2=4

8 0
3 years ago
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