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Sauron [17]
3 years ago
14

A recursive rule for a geometric sequence is a1=4/9;an=3an−1

Mathematics
2 answers:
Rudik [331]3 years ago
5 0
The answer is (4/9)(3)^n-1
Mrac [35]3 years ago
3 0

Answer:

Explicit rule for this sequence is, a_n = 49\cdot (3)^{n-1}

Step-by-step explanation:

A recursive rule for a geometric sequence is a_1=49, a_n = 3a_{n-1}

First term a_1= 49

To get second term, just multiply the first term by 3

a_n = 3 a_{n-1}

a_2 = 3 a_1

a_2= 3\cdot 49

so, we get the common ratio r = 3

Now, Explicit rule for geometric sequence is given by:

a_n = a_1 \cdot (r)^{n-1}

Here, a_1= 49 and r= 3

So, explicit rule is :

a_n = 49\cdot (3)^{n-1}

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