Answer:
C
Step-by-step explanation:
Line of symmetry
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
(3, 50) and (14,303)
Step-by-step explanation:
Given the system of equations;
y=23x–19 ....1
x²–y= – 6x–23 ...2
Substitute 1 into 2;
x²–(23x-19)= – 6x–23
x²–23x+19= – 6x–23 .
x²-23x + 6x + 19 + 23 = 0
x² - 17x + 42 = 0
Factorize;
x² - 14x - 3x + 42 = 0
x(x-14)-3(x-14) = 0
(x-3)(x-14) = 0
x = 3 and 14
If x = 3
y = 23(3) - 19
y = 69-19
y = 50
If x = 14
y = 23(14) - 19
y = 322-19
y = 303
Hence the coordinate solutions are (3, 50) and (14,303)
Answer:
<h2><em>
y = 8, ST = 31 and RT = 81</em></h2>
Step-by-step explanation:
Given RS = 6y+2, ST=3y +7, and RT=13y-23, the vector formula is true for the equations given; RS+ST = RT
Om substuting the expression into the formula;
6y+2+3y +7 = 13y - 23
collect the like terms
6y+3y-13y+2+7+23 = 0
-4y+32 = 0
Subtract 32 from both sides
-4y+32-32 = 0-32
-4y = -32
y = -32/-4
y = 8
Since ST = 3y+7. we will substitute y = 8 into the exprrssion to get ST
ST = 3(8)+7
ST = 24+7
ST = 31
Similarly,
RT = 13y-23
RT = 13(8)-23
RT = 104-23
RT = 81
<em>Hence y = 8, ST = 31 and RT = 81</em>
Answer:
6600
Step-by-step explanation:
6600
