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Ksenya-84 [330]

3 years ago

8

A typing service charges $5.00 per pages Mrs Daniel does not want to spend more than $25 for typing What is the maximum number o

f pages she can have typed

1 answer:

erma4kov [3.2K]3 years ago

7 0

It would be 5 pages for under $25

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Find a counter example to following bad definition: a square has four right angles

Schach [20]

a flat figure with 4 equal straight sides and four right angles

5 0

3 years ago

Read 2 more answers

Brainliest if correct! Please explain how this is done!

Korvikt [17]

The value of csc C in fraction and in decimal form is as follows:

csc C = 5 / 3

csc C = 1.66666666667

Using trigonometric ratio,

secant A = 1 / cos A = hypotenuse / adjacent

Therefore,

sec A = 5/3

sec A = 1 / cos A

cos A = adjacent / hypotenuse

cos A = 3 / 5

A = cos⁻¹ 0.6

A = 53.1301023542

Therefore,

∠A = 53°

∠B = 90°

∠C = 180 - 143 = 37°

cosec C = 1 / sin C = hypotenuse / opposite

cosec C = 5 / 3

learn more about trigonometry here: brainly.com/question/25942962?referrer=searchResults

5 0

2 years ago

Solve the system, or show that it has no solution. (If there is no solution, enter NO SOLUTION. If there are an infinite number

liberstina [14]

Answer:

The system has an infinite set of solutions $(x,y) = (x, \frac{x-5}{4})$

Step-by-step explanation:

From the first equation:

$20x - 80y = 100$

$20x = 100 + 80y$

$x = \frac{100 + 80y}{20}$

$x = 5 + 4y$

Replacing on the second equation:

$-14x + 56y = -70$

$-14(5 + 4y) + 56y = -70$

$-70 - 56y + 56y = -70$

$0 = 0$

This means that the system has an infinite number of solutions, considering:

$x = 5 + 4y$

$4y = x - 5$

$y = \frac{x - 5}{4}$

The system has an infinite set of solutions $(x,y) = (x, \frac{x-5}{4})$

8 0

3 years ago

Jack has two more than half as many cups as

Rufina [12.5K]

Step-by-step explanation:

$(x \div 2 + 2) + \frac{(x \div 2 + 2)}{2} + x$

its hard to determine without the known value of x, but the above would be the equation needed to solve it if you knew what x was

4 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

The degrees of freedom are given by:

$df=n-1=20-1=19$

Since the Confidence is 0.90 or 90%, the significance $\alpha=0.1$ and $\alpha/2 =0.05$ , the critical values for this case are:

$\chi^2_{\alpha/2}=30.144$

$\chi^2_{1- \alpha/2}=10.117$

And replacing into the formula for the interval we got:

$\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

Part c

Now we just take square root on both sides of the interval and we got:

$23.818 \leq \sigma \leq 41.112$

5 0

3 years ago