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Ksenya-84 [330]

3 years ago

8

A typing service charges $5.00 per pages Mrs Daniel does not want to spend more than $25 for typing What is the maximum number o

f pages she can have typed

1 answer:

erma4kov [3.2K]3 years ago

7 0

It would be 5 pages for under $25

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YESSSSS 100% down

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3 years ago

Read 2 more answers

Write the following equations in slope intercept form

Rus_ich [418]

Answer:

problem 1 2x+5y= 0

×=-1/2-5/2y

problem 2 y=1 3/7y y=-1.428571

7y=-10

problem 3 x=-7

problem 4 x-y=20

x=-20

7 0

3 years ago

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

2)

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

3 years ago

oceanside bike rental shop charges a $17 fixed fee plus six dollars an hour for renting a bike. Tim paid $47 to rent a bike. How

gavmur [86]

Approximately 8 hours

8 0

3 years ago

15. Find the length of segment DE of the triangle ABC.

ruslelena [56]

Answer:

Option C. $26\ units$

Step-by-step explanation:

we know that

Triangles ADE and ABC are similar by AA similarity postulate

AB=2AD

Apply proportion

$\frac{AD}{AB}=\frac{8x-6}{12x+4}\\ \\\frac{AD}{2AD}=\frac{8x-6}{12x+4}\\ \\\frac{1}{2}=\frac{8x-6}{12x+4}\\ \\12x+4=16x-12\\ \\16x-12x=4+12\\ \\4x=16\\ \\x=4\ units$

Find the length of segment DE

$DE=8x-6=8(4)-6=26\ units$

4 0

3 years ago