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3 years ago

What is the area of a square that has a side length of 1/5 of an inch?

2 answers:

8 0

1/5 is 0.2 inches. 0.2 * 0.2 is 0.04 inches, AKA 1/25 of an inch.
(you could just square the bottom number of the fraction 1/5 for an easy way ;))

gladu [14]3 years ago

7 0

0.04 inches squared - because it's 0.2 inches squared.

This can also be written as 1/25 inches squared

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What is the LCD of 2/7 and 12/5

SashulF [63]

Answer:

10/35 84/35

Step-by-step explanation:

2/7 12/5

7 × 5 = 35

2 × 5 = 10

12 × 7 = 84

10/35 84/35

4 0

3 years ago

Who cant help me with 1-6 ‍♀️♥️

GarryVolchara [31]

1)80
2)55
3)D
4)F
5)-20
6)B
Hope that helps

5 0

3 years ago

How many solutions does the equation have? 6x+4x-6=24+9x

babunello [35]

Combine like terms.
10x+6=24+9x

Put variables to one side and the constants to another.
x=-18

There is only one solution.

Hope this helps!

5 0

3 years ago

The graph of g(x) resembles the graph of f(x)=x^2, but it has been changed. Which of these is the equation of g(x)?

siniylev [52]

Answer:

Step-by-step explanation:

Anwer A has the following equation:

$g(x)=\frac{3}{5}x^2-3$

In this equation, we can calculated the intercept replacing x by 0, as:

$g(x)=\frac{3}{5}0^2-3=-3$

if this is the answer, the graph of g(x) should be through the point (0,-3) and that happens.

Additionally, the roots of the equations are calculated replacing g(x) by 0 and solving for x, so:

$0=\frac{3}{5}x^2-3\\x_1=\sqrt{5}=2.236\\x_2=-\sqrt{5}=-2.236$

It means that the graph of g(x) should be through the points (2.236,0) and (-2.236,0) and that happens too.

So, the answer is A, $g(x)=\frac{3}{5}x^2-3$

7 0

3 years ago

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

4 0

3 years ago