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3 years ago

Math is hard, 7th grade math too..

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

3 0

Answer:

i could be wrong but i think its x=3 :(

Step-by-step explanation:

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Each week, Heather’s company has $5000 in fixed costs plus an additional $250 for each system produced. The company is able to p

kvv77 [185]

The question is an illustration of composite functions.

Functions c(n) and h(n) are $\mathbf{c(n) = 5000 + 250n}$ and $\mathbf{n(h) = 5h}$
The composite function c(n(h)) is $\mathbf{c(n(h)) = 5000 + 1250h}$
The value of c(n(100)) is $\mathbf{c(n(100)) = 130000}$
The interpretation is: "the cost of working for 100 hours is $130000"

The given parameters are:

$5000 in fixed costs plus an additional $250
5 systems in one hour of production

(a) Functions c(n) and n(h)

Let the number of system be n, and h be the number of hours

So, the cost function (c(n)) is:

$\mathbf{c(n) = Fixed + Additional \times n}$

This gives

$\mathbf{c(n) = 5000 + 250 \times n}$

$\mathbf{c(n) = 5000 + 250n}$

The function for number of systems is:

$\mathbf{n(h) = 5 \times h}$

$\mathbf{n(h) = 5h}$

(b) Function c(n(h))

In (a), we have:

$\mathbf{c(n) = 5000 + 250n}$

$\mathbf{n(h) = 5h}$

Substitute n(h) for n in $\mathbf{c(n) = 5000 + 250n}$

$\mathbf{c(n(h)) = 5000 + 250n(h)}$

Substitute $\mathbf{n(h) = 5h}$

$\mathbf{c(n(h)) = 5000 + 250 \times 5h}$

$\mathbf{c(n(h)) = 5000 + 1250h}$

(c) Find c(n(100))

c(n(100)) means that h = 100.

So, we have:

$\mathbf{c(n(100)) = 5000 + 1250 \times 100}$

$\mathbf{c(n(100)) = 5000 + 125000}$

$\mathbf{c(n(100)) = 130000}$

(d) Interpret (c)

In (c), we have: $\mathbf{c(n(100)) = 130000}$

It means that:

The cost of working for 100 hours is $130000

Read more about composite functions at:

brainly.com/question/10830110

5 0

3 years ago

SOLVING EACH SYSTEM BY ELIMINATION x+3y=5 x=-6y+14 HELP

nata0808 [166]

Answer:

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

Step-by-step explanation:

Given the system of the equations

$x+3y=5;\:x=-6y+14$

solving by elimination method

$\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}$

$\mathrm{Arrange\:equation\:variables\:for\:elimination}$

$\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}$

$x+6y=14$

$-$

$\underline{x+3y=5}$

$3y=9$

$\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}$

solve $3y=9$ for $y$ :

$3y=9$

$\frac{3y}{3}=\frac{9}{3}$

$y=3$

$\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3$

Solve $x+3\cdot \:3=5$ for x:

$x+3\cdot \:3=5$

$x+9=5$

$x=-4$

Therefore,

$\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}$

$x=-4,\:y=3$

6 0

3 years ago

What is the answer to -6(4r+2)+5

RideAnS [48]

Answer:

-24r - 7

Step-by-step explanation:

-6(4r + 2) + 5

-24r - 12 + 5

-24r - 7

Best of Luck!

5 0

3 years ago

18x + 101 = 4 91 – 51'= -1 help me pleasee

juin [17]

Distribute the -9 into the values in the parentheses.

STEP BY STEP

-9(-2x-3)

-9*-2x=18x

-9*-3=27

Therefore, the equation then becomes: 18x+27.

The answer is the first choice, or A.

3 0

3 years ago

Find the value of x 7 17 x*

AlladinOne [14]

Answer:

the awnser is 24

8 0

3 years ago