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3 years ago

A material that transmits nearly all the light in a ray because it offers little resistance to the light is

Physics

2 answers:

Amanda [17]3 years ago

7 0

The answer is D, transparent

ioda3 years ago

7 0

Penn Foster Students: Transparent

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A 4 kg block is pulled with 5.6 N of force to the right. The block experiences 1.1 N of friction. What is the acceleration of th

BARSIC [14]

Answer:

The acceleration of the box is 1.125 m/s² towards right.

Explanation:

Mass of the box, $m=4$ kg

Force acting towards right, $F=5.6$ N

Frictional force acting towards left, $f=1.1$ N

Let the acceleration be $a$ m/s².

Now, net force acting on the box towards right is given as:

$F_{net}=F-f=5.6-1.1=4.5\textrm{ N}$

From Newton's second law of motion,

$F_{net}=ma\\4.5=4a\\a=\frac{4.5}{4}=1.125\textrm{ }m/s^2$

Therefore, the acceleration of the box is 1.125 m/s² towards right.

7 0

4 years ago

Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.

77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0

2 years ago

Some help me on this please

satela [25.4K]

Answer:

Changes in the object's momentum (answer D)

Explanation:

A net force will cause an object to change its velocity, and that will affect the object's momentum, which is defined by the product of the object's mass times its velocity.

So, select the last option (D) in the given list.

8 0

3 years ago

A boy on a swing set has a speed of 4.5 m/s and a centripetal acceleration of 8.1 m/s2 at the bottom of his swing. How long are

EleoNora [17]

Answer:

R = 1.8 m

Explanation:

This is a simple harmonic movement exercise, at the bottom of the swing the acceleration is vertical upwards and the speed is tangential to the trajectory, that is horizontal; the expression for the centralized acceleration is

$a_{c}$ = v² / R

R = v² /a_{c}

where the radius is equal to the length of the swing

let's calculate

R = 8.1 / 4.5

R = 1.8 m

5 0

3 years ago

A low orbit satellite at 100 km altitude had a camera that resolved a car location to within 0.3 meter. Find the minimum diamete

NeX [460]

Answer:

Minimum diameter of the camera lens is 22.4 cm

The focal length of the camera's lens is 300cm

Explanation:

y = Resolve distance = 0.3 m

h = Height of satellite = 100 km

λ = Wavelength = 550 nm

Angular resolution

$tan\theta\approx \theta =\frac{y}{h}\\\Rightarrow \theta=\frac{0.3}{100\times 10^3}=3\times 10^{-6}$

From Rayleigh criteria

$sin\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{sin\theta}\\\Rightarrow D=1.22\frac{550\times 10^{-9}}{sin3\times 10^{-6}}=0.2236\ m=22.4\ cm$

Minimum diameter of the camera lens is 22.4 cm

Relation between resolvable feature, focal length and angular resolution

$d=f\Delta \theta\\\Rightarrow f=\frac{d}{\Delta \theta}\\\Rightarrow f=\frac{9\times 10^{-6}}{3\times 10^{-6}}=3\ m=300\ cm$

The focal length of the camera's lens is 300cm

3 0

3 years ago