Explanation: To determine how long it takes for the ball to return to the point of release and considering it is a free fall system, we can use the given formula:

$d=v_{0}.t + \frac{1}{2} .a.t^{2}$ , where:

d is the distance the ball go through;

v₀ is the initial velocity, which is this case is 0 because he releases the ball;

a is acceleration due to gravity;

t is the time necessary for the fall;

Suppose <em>h</em> is the height from where the ball was dropped.

On Earth:

h=0.t + $\frac{1}{2}.10.t^{2}$

h = 5t²

$t_{T}$ = $\sqrt{\frac{h}{5} }$

On the other planet:

h = 0.t + $\frac{1}{2}.30.t^{2}$

h = 15.t²

$t_{P}$ = $\sqrt{\frac{h}{15} }$

Comparing the 2 planets:

$\frac{t_{T} }{t_{P} } = \frac{\sqrt{\frac{h}{5} } }\sqrt{{\frac{h}{15} } }$

$\frac{t_{T} }{t_{P} }$ = $\sqrt{3}$ or $t_{T} = \sqrt{3}.t_{P}$

Comparing the two planets, on the massive planet, it will take more time to fall the height than on Earth. In consequence, it will take more time to return to the initial point, when it was released.

5 0

3 years ago

A racecar is traveling at a speed of 80.0 m/s on a circular

Simora [160]

A :-) F = mv^2 by r
Given - m = 500 kg
v = 80.0 m/s
r = 450 m
Solution -
F = mv^2 by r
F = 500 x (80)^2 by 450
F = 500 x 6400 by 450
( cut 500 and 450 because 5 x 100 = 5 , 5 x 90 = 450 and also 90 and 6400 because 90 x 70 = 6400 )
F = 100 x 70
F = 7000

.:. The centripetal force is 7000 N

7 0

3 years ago

Read 2 more answers

Help Please? Hshshahahahshshhs

pickupchik [31]

the answer is no change

7 0

3 years ago