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3 years ago

How do i solve this?

Mathematics

1 answer:

Goryan [66]3 years ago

8 0

For this, I got the equation (X+3)^2-2 or X^2+6X+7. I used this method:

First I set up an equation (X+H)^2-K, where (K, H) is the vertex. All we have to do is find where the graph reaches its minimum value (because it opens upwards), then find the x-coordinate that lies there, which is (-2,3). Substituting these value in for H and K, we get the equation (X+3)^2-2 or simplified X^2+6X+7.

:)

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The length of a rectangle is 1/4 ft. it's width is 1 1/2 ft. what is the perimeter?

Mrac [35]

Answer

11.5 ft

Step-by-step explanation:

Perimeter of rectangle:2(l+w)

l :1/4 ft w:11/2 ft

2(1/4+11/2)=11.5

7 0

3 years ago

Read 2 more answers

Sherrie invested some money at 6% interest. Sherrie also invested $249 more than 4 times that amount at 12%. How much is investe

Anon25 [30]

Answer:

6%: $1776
12%: $7353

Step-by-step explanation:

Let x represent the amount invested at 6%. Then the amount invested at 12% is 4x+249. Sherrie's interest is ...

0.06x +0.12(4x +249) = 988.92

0.54x + 29.88 = 988.92

0.54x = 959.04

x = 959.04/0.54 = 1776

4x+249 = 7353

Sherrie invested $1776 at 6% and $7353 at 12%.

4 0

3 years ago

Which is the same as 10-2? A) 0.0001 B) 0.001 C) 0.01 D) 100

IceJOKER [234]

The correct answer is C. This is because
10^-2 = 1/10^2 which is 0.01

3 0

3 years ago

Find the slope between (3,2) and (-2,3)

blagie [28]

$(x_1;\ y_1);\ (x_2;\ y_2)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(3;\ 2);\ (-2;\ 3)\\\\\boxed{m=\dfrac{3-2}{-2-3}=\dfrac{1}{-5}=-\dfrac{1}{5}}$

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3 years ago

Learning goal: to understand the rules for computing dot products. let vectors a=(2,1,−4), b=(−3,0,1), and c=(−1,−1,2). part a -

miv72 [106K]

For this case we have the following vectors:
$a = (2,1, -4)

b = (- 3,0,1)

c = (- 1, -1,2)$
The dot product of two vectors is a scalar.
The point product consists of multiplying component by component and then adding the result of the multiplication of each component.
For the product point of the vectors a and b we have:
$a.b = (2,1, -4). (- 3,0,1)

a.b = (2) (- 3) + (1) (0) + (-4) (1)

a.b = - 6 + 0 - 4

a.b = - 10$
Answer:
The product point of the vectors a and b is:
$a.b = - 10$

3 0

3 years ago