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2 years ago

8

In basketball, Katrina makes 6 out of every 9 free throws. Her coach claims that if she tries 15 free throws she should make 10

of them. I coach's claim correct?

2 answers:

zloy xaker [14]2 years ago

5 0

Yes, Thats 2/3 rds of the equation

maxonik [38]2 years ago

5 0

Yes that is true!!!!

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The vertices of ΔRST are R(–1,–1), S(–1,11) and T(4,11). Which could be the side lengths of a triangle that is similar but not c

Step2247 [10]

The side lengths could be 10, 24 and 26 units.

We must first find the side lengths. We use the distance formula to do this.

For RT:
$d=\sqrt{(11--1)^2+(-1--1)^2}
\\=\sqrt{(11+1)^2+(-1+1)^2}
\\=\sqrt{12^2+0^2}=\sqrt{144}=12$

For ST:
$d=\sqrt{(11-11)^2+(4--1)^2}
\\=\sqrt{0^2+(4+1)^2}=\sqrt{5^2}=\sqrt{25}=5$

For TR:
$d=\sqrt{(11--1)^2+(4--1)^2}
\\=\sqrt{(11+1)^2+(4+1)^2}=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13$

Our side lengths, from least to greatest, are 5, 12 and 13.

To be similar but not congruent, the side lengths must have the same ratio between corresponding sides but not be the same length. 10, 24 and 26 are all 2x the original side lengths, so this works.

5 0

2 years ago

Manuel bought 17 pounds of flour for $7. How many dollars did he spend per pound?

harkovskaia [24]

.41 dollars a pound
.25 dollars an hour

4 0

2 years ago

What does M equal in 4-m/2=10

Verizon [17]

Simplify both sides of your equation.

Subtract 4 from both sides.

Multiply both sides by 2(-1).

m = -12

3 0

2 years ago

In the year 2000, the population of a city was 600,000 citizens. The population increases at a rate of 1.8% per year.

Alona [7]

Y=600000(1+1.8%)^(x-2000)
So the population in 2012
Y=600,000×(1+0.018)^(2,012−2,000)
Y=743,232

6 0

2 years ago

Read 2 more answers

Joelle is working on a school report in a word processor. She wants to place an oversized image which is 30.51 \text{ cm}30.51 c

ehidna [41]

Answer:

the horizontal position for the left edge of the image is -4.46 cm.

Step-by-step explanation:

The horizontal midpoint of the page is:

21.59 / 2 = 10.79 cm

The horizontal midpoint of the image is given as:

30.51 / 2 = 15.25 cm

These midpoints must be on the same point in the axis.

By taking the leftmost edge of the paper to be point zero on the axis, then, the distance accommodated by the paper is 10.795 cm.

The distance that goes beyond this leftmost edge is computed as;

This is on the negative side on the axis.

Thus the horizontal position for the left edge of the image is -4.46 cm.

3 0

2 years ago