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34kurt
3 years ago
9

U − -23 _______ = -8 -9 Solve for u Thanks!

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

Answer:

u=95

Step-by-step explanation:

To solve this problem we need to isolate 'u' variable using properties of equation.

Lets multiply by -9 the whole equation

u - -23=-8*9

Remember keys features of algebra:

- * - = +

- * += -

+ * - = -

+ * + =+

So, our equations becomes>

u+23=-72

Lets now subtract 23 to both sides

u-23=-72-23

We have u=95

iren2701 [21]3 years ago
6 0

Answer:

24 So simply plug the number in for the variable and you get 47 – 23 = 24.

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Answer:

2

Step-by-step explanation:

<u>Given AP where:</u>

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<u>To find</u>

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<u>Since</u>

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<u>Initial equations will change as:</u>

  • a₁ + 3d = 2(a₁ + d) - 1  ⇒  a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
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4 years ago
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Determine the next step for solving the quadratic equation by completing the square.
nexus9112 [7]

\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

the idea behind the completion of the square is simply using a perfect square trinomial,  hmmm usually we do that by using our very good friend Mr Zero, 0.

if we look at the 2nd step, we have a group as x² - x, hmmm so we need a third element, which will be squared.

keeping in mind that the middle term of the perfect square trinomial is simply the product of the roots of "a" and "b",  so in this case the middle term is "-x", and the 1st term is x², so we can say that

\stackrel{middle~term}{2(\sqrt{x^2})(\sqrt{b^2})~}~ = ~~\stackrel{middle~term}{-x}\implies 2xb~~ = ~~~~ = ~~-x \\\\\\ b=\cfrac{-x}{2x} \implies b=-\cfrac{1}{2}

so that means that our missing third term for a perfect square trinomial is simply 1/2, now we'll go to our good friend Mr Zero, if we add (1/2)², we have to also subtract (1/2)², because all we're really doing is borrowing from Zero, so we'll be including then +(1/2)² and -(1/2)², keeping in mind that 1/4 - 1/4 = 0, so let's do that.

-3~~ = ~~-2\left[ x^2-x+\left( \cfrac{1}{2} \right)^2 ~~ - ~~\left( \cfrac{1}{2} \right)^2\right]\implies -3=-2\left(x^2-x+\cfrac{1}{4}-\cfrac{1}{4} \right) \\\\\\ -3=-2\left(x^2-x+\cfrac{1}{4} \right)+(-2)-\cfrac{1}{4}\implies -3=-2\left(x^2-x+\cfrac{1}{4} \right)+\cfrac{1}{2} \\\\\\ -3-\cfrac{1}{2}=-2\left(x^2-x+\cfrac{1}{4} \right)\implies -\cfrac{7}{2}=-2\left(x-\cfrac{1}{2} \right)^2\implies \cfrac{7}{4}=\left(x-\cfrac{1}{2} \right)^2

~\dotfill\\\\ \pm\sqrt{\cfrac{7}{4}}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}=x-\cfrac{1}{2}\implies \cfrac{\pm\sqrt{7}}{2}+\cfrac{1}{2}=x \implies \cfrac{\pm\sqrt{7}+1}{2}=x

8 0
2 years ago
-5p - 12= 19<br>what does p equal
Nina [5.8K]

Answer:

p =  31/-5

Step-by-step explanation:

Step 1: Add 12 to both sides.

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−5p=31

Step 2: Divide both sides by -5.

−5p /−5  =  31/−5

p=  −31 /5

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