To solve this problem, we can use the tan function to find
for the distances covered.
tan θ = o / a
Where,
θ = angle = 90° - angle of depression
o = side opposite to the angle = distance of boat from
lighthouse
a = side adjacent to the angle = height of lighthouse = 200
ft
When the angle of depression is 16°18', the initial distance
from the lighthouse is:
o = 200 tan (90° - 16°18')
o = 683.95 ft
When the angle of depression is 48°51', the final distance
from the lighthouse is:
o = 200 tan (90° - 48°51')
o = 174.78 ft
Therefore the total distance the boat travelled is:
d = 683.95 ft - 174.78 ft
<span>d = 509.17
ft</span>
Answer:
rounding to the nearest tenth
Step-by-step explanation:
It would be -5. assuming that back is negative and forward is positive, Kyle has moved a total of 5 spaces back
The correct answer is C. 6(x-4)
Answer: Obtuse angle. Obtuse angles are any angle above 90 degrees. Acute angles are any angle below 90 degrees. 90 degree angles are right angles
