Which equation could be used to solve for the length of XY?

Mathematics

2 answers:

Dafna11 [192]3 years ago

5 0

Answer:D

Step-by-step explanation:

dem82 [27]3 years ago

3 0

We are looking for the hypotenuse in this right triangle. The reference angle is 41 degrees. We have that angle and the side that is opposite that angle, 22, so the trig identity that we will use that relates the side opposite to the hypotenuse is sin. Our ratio would be set up like this: $sin(41)= \frac{22}{xy}$ . Solving for xy we will have $xy= \frac{22}{sin(41)}$ , choice D from above.

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Expand the polynomial and simplify: (4xy− 1 8 y^2)^2

Vinvika [58]

Answer: $4y^{2}(2x-9y)^{2}$

Step-by-step explanation:

We have the following polynomial:

$(4xy-18y^{2})^{2}$

This is a polynomial of the form $(a-b)^{2}=a^{2}-2ab+b^{2}$ . Following this rule to expand it, we have:

$(4xy)^{2}-2(4xy)(18y^{2})+(18y^{2})^{2}$

$16x^{2}y^{2}-144xy^{3}+324y^{4}$

Applying common factor $4y^{2}$ :

$4y^{2}(4x^{2}-36xy+81y^{2})$

Note the polynomial inside the parenthesis is a perfect square trinomial, which can be factored to $(2x-9y)^{2}$ . Hence, the final simplification is: