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Maru [420]
3 years ago
14

Based on the trends within the periodic table of elements, decide which of the following elements has the same number of orbital

s?
A. Cu, Ag, Au

B. N, O, F

C. Be, Mg, Ca

D. B, Si, As
Chemistry
1 answer:
hammer [34]3 years ago
6 0

Answer:

B.  N, O, F

Explanation:

Elements in same row of periodic table will have same number of orbitals.

In option A C and D elements are of different row due to which they posses different number of orbitals.

But in option B.  N, O, F are in second row of periodic table so same orbitals.

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Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
4 years ago
A substance with two or more different types of atoms chemically bonded together is called....
Slav-nsk [51]

Answer:

D

Explanation:

7 0
3 years ago
What else is produced when sodium carbonate decomposes?<br> Na2Co3 - Na2O+
AleksandrR [38]

Answer:When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is .

The decomposition of sodium carbonate is:

The decomposition of sodium bicarbonate,  will result in the formation of sodium oxide,  and carbon dioxide, .

Hence, carbon dioxide,  will produce with sodium oxide,  on decomposition of .

Explanation:Na2CO3 Na2O +CO2   CO2 is the answer

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