C. Accelerating should be the correct onw
There are 2 moles of O stones present in 88 grams of CO2. Why? Well, we can find the amount of moles present in 88 grams of CO2 by dividing the mass by the molar mass. The mass of CO2 comes out to be 88 grams. The molar mass of CO2 comes out to be 44 grams. Because 88 is the mass of CO2 and 44 is the molar mass of CO2, we can divide 88 by 44 to identify that there are 2.0 moles of O atoms present in 88 grams of CO2.
Your final answer: There are 2.0 moles of O atoms present in 88 grams of CO2. Your final answer to this question is D, or 2.0 moles. If you need to better understand, let me know and I will gladly assist you.
To calculate the average mass of the element, we take the summation of the product of the isotope and the percent abundance. We calculate as follows:
Average atomic mass = .374 ( 184.953 amu ) + .626 ( <span>186.958 amu ) = 186.208 amu
Hope this answers the question. Have a nice day.</span>
When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.
given that :
volume = 1.00 L
molarity = 0.500 M
The solution is tripled by dilution but there will be no effect in number of mole by the dilution.
the number of moles = molarity × volume in L
the number of moles = 1 × 0.500
the number of moles = 0.5 mol
Thus, When 1.00 L of a 0.500 M LiBr solution is tripled by dilution with water . the number of moles of lithium in new solution is 0.5 moles.
To learn more about number of moles here
brainly.com/question/14919968
#SPJ4
Answer:
Double replacement reaction
Explanation:
This is what is known as a double replacement reaction. The two parts of each molecule separate and recombine to form two new compounds. For instance, 
separates into 
and 
, while 
separates into 
and 
, and then they recombine with the other compound.
Hope this helps!
