Answer:
B. (-1,7)
C. (0,5)
D. (2,3)
Step-by-step explanation:
We solve this question looking at the graphic.
A. (-7, 1)
When
, and thus (7,-1) is not solution of the equation.
B. (-1,7)
When
, and thus (-1,7) is a solution of the equation.
C. (0,5)
When
, and thus (0,5) is a solution of the equation.
D. (2,3)
When
, and thus (2,3) is a solution of the equation.
E. (3, 2)
When
, and thus (3,2) is not part of the solution
F. (5,0)
When
, and thus (5,0) is not part of the solution
P(parentheses)
E(exponents)
M(multiplication)
D(division)
A(addition)
S(subtraction)
I did 2-
d) Square root of 16 plus 3 to the second power (exponent)
3 to the 2nd power = 9
square root of 16 is 4 so 9+4=13
g) Square root of 25 to the power of 2 + (2+3)
2+3= 5 then square root of 25 = 5 to the second power is 25 = 30
Step-by-step explanation:
sleeping in class ? :-)
these are our pure definition questions.
9. false
if the data was only defined for whole numbers, then that would be the only case, where that is true. but then, there would be no rounding.
the "significant figures" are the decimal places after the decimal point.
rounding it to one significant figure means rounding it to the first position after the decimal point.
10. True
see 9. for more details.
Answer:
B. 28.1
Step-by-step explanation:
By the property of intersecting secant and tangent out side of the circle.
![20 \times (20 + x) = {31}^{2} \\ 20(20 + x) = 961 \\ 20 + x = \frac{961}{20} \\ 20 + x = 48.05 \\ x = 48.05 - 20 \\ x = 28.05 \\ \huge \red{ \boxed{x = 28.1}}](https://tex.z-dn.net/?f=20%20%5Ctimes%20%2820%20%2B%20x%29%20%3D%20%20%7B31%7D%5E%7B2%7D%20%20%5C%5C%2020%2820%20%2B%20x%29%20%3D%20961%20%5C%5C%2020%20%2B%20x%20%3D%20%20%5Cfrac%7B961%7D%7B20%7D%20%20%5C%5C%2020%20%2B%20x%20%3D%2048.05%20%5C%5C%20x%20%3D%2048.05%20-%2020%20%5C%5C%20x%20%3D%2028.05%20%5C%5C%20%20%5Chuge%20%5Cred%7B%20%5Cboxed%7Bx%20%3D%2028.1%7D%7D)