Answer:
110 grams
Step-by-step explanation:
CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).
So first finding the mass of 1 molecule of CO2 which is equals to
= mass of 1 carbon atom + masses of 2 oxygen atom, we get
= 12+(16*2)= 12+32= 44 a.m.u.
Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )
1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams
So our answer is 110 grams.
lowkey hope this helped you, good luck whatever you need it for Imaooo
Answer:
2/5.
Step-by-step explanation:
The prime numbers from 1 to 20 are 2, 3, 5, 7, 11, 13, 17 and 19.
A total of 8.
So the probability of rolling a prime number is 8/20
= 2/5.
Answer: 2 and 6
Step-by-step explanation:
Figure out how
The domain of a function is the set of x values for which it is defined. The range of the given graph will be -2≤x<7.
<h3>What is the domain and range of a function?</h3>
The domain of a function is the set of x values for which it is defined, whereas the range is the set of y values for which it is defined.
As it can be seen that the value on the y-axis is defined for every value of x between -2 to 7, also the value of x is also defined for x=-2.
Hence, the range of the given graph will be -2≤x<7.
Learn more about Domain and Range:
brainly.com/question/1632425
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Answer:
Step-by-step explanation:
To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.
<em>Remove the fraction by multiplying (d +3) on both sides:</em>
<em>Expand</em><em>:</em>
<em>
</em>
<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>
<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>
<em>
</em>
<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
<em></em>
