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grin007 [14]
3 years ago
13

What is 5,370,288 rounded to the nearest 100,000

Mathematics
2 answers:
Illusion [34]3 years ago
5 0
5,400,000

That should be the answer since the 7 is next to the 3 it would round up 1 so the 3 becomes a 4.
umka21 [38]3 years ago
4 0
Since the 7 in the 10,000s place is greater than or equal to 5, we're going to round upwards. The 3 will become a 4 when we round up. This leaves us with 5,400,000.
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15. Solve for the specified variable:<br> -<br> х<br> +<br> 7 8<br> - 10; for y.
Andreyy89

Answer:

y=80-\frac{8x}{7}

Step-by-step explanation:

15). Given equation is,

     \frac{x}{7}+ \frac{y}{8}=10

     Multiply the equation by 8,

     8(\frac{x}{7}+ \frac{y}{8})=10\times 8

     \frac{8x}{7}+y=80

     Subtract \frac{8x}{7} from both the sides of the equation,

     \frac{8x}{7}+y-\frac{8x}{7}=80-\frac{8x}{7}

     y=80-\frac{8x}{7}

     Therefore, value of the variable 'y' will be,

     y=80-\frac{8x}{7}

3 0
2 years ago
Which of the following statements are true?
lana [24]

Answer:

B, C, E, & F

Step-by-step explanation:

Option A is incorrect because the equation Ax = b is referred to as a matrix equation, not a vector equation.

Option B is correct. If Ax = b has a solution, vector b will a linear combination of columns of matrix A.

Option C is correct. In a matrix equation, product Ax when defined, is a sum of products.

Option D is incorrect. If an augmented matrix [Ab] had a pivot position in every row, there could be a pivot in the last column which would make it inconsistent.

Option E is correct. If the columns of an m×n matrix A spanR^m, then the equation Ax=b is consistent for each b in

Option F is correct. IfA is an m x n matrix whose columns do not span, then the equation Ax = b is inconsistent for some b in R^m

Options B, C, E, and F are correct.

7 0
3 years ago
Help Geometry only help on even numbers check if correct
kompoz [17]

Answer:

everything is correct

Step-by-step explanation:

you did a good job

8 0
1 year ago
Which sets of three numbers could represent the lengths of the sides of a right triangle? 12, 15, 21
castortr0y [4]

Look at the pictures! :)

HOPE THIS HELPED! HAVE A GREAT DAY! :)

6 0
3 years ago
In a survey, the planning value for the population proportion is . How large a sample should be taken to provide a confidence in
tatuchka [14]

Answer:

n=350

Step-by-step explanation:

Notation and definitions

n random sample taken  (variable of interest)

\hat p=0.35 estimated proportion  (value assumed)

p true population proportion

Confidence =0.95 or 95% (value assumed)

Me=0.05 (value assumed)

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.586  

And rounded up we have that n=350

4 0
2 years ago
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