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hram777 [196]
4 years ago
14

The boiling point of a substance is a chemical property true or false​

Chemistry
2 answers:
Rasek [7]4 years ago
8 0

the answer is false:)

pogonyaev4 years ago
4 0

Explanation:

vraiLe point d'ébullition est la température à laquelle une substance passe de la phase liquide à la phase gazeuse

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3. Once magnesium (Mg) gives up electron(s) to become an ion, it will become
xeze [42]

Answer:

Option B. Cation that is smaller than the original atom.

Explanation:

Magnesium is a divalent element. This implies that magnesium can give up 2 electrons to become an ion (cation) as shown below:

Mg —> Mg²⁺ + 2e¯

Next, we shall write the electronic configuration of magnesium atom (Mg) and magnesium ion (Mg²⁺). This can be written as follow:

Mg (12) = 2, 8, 2

Mg²⁺ (10) = 2, 8

From the above illustration, we can see that the magnesium atom (Mg) has 3 shells while the magnesium ion (Mg²⁺) has 2 shells.

This simply means that the magnesium ion (Mg²⁺) i.e cation is smaller that the original magnesium atom (Mg).

5 0
3 years ago
2. List the following from least complex to most complex.
nekit [7.7K]

Answer:

Bacterial cell, cell with a nucleus, multicellular organism

7 0
3 years ago
Read 2 more answers
Calculate how many grams of oxygen form when 2.72 g of KCIOg reacts completely given the
34kurt

1.06g

Please refer to the image attached.

You first find the number of moles (n) for KClO3 as you have been given the mass. So n = mass/Mr gives you the moles that is 0.022 mol

Next you use the ratio 2:3 as per the equation where it's 2KClO3 ---> 3O2 so you just cross multiply and get the moles for oxygen.

Now that you know the number of moles for oxygen, you can use the same moles equation that you used earlier to find the mass. mass=n×Mr and so you get the answer as 1.06g of oxygen.

4 0
3 years ago
Calculate the ΔG°' for the reaction with 3 significant figures with no label for the dimension (just the number). fructose-6-pho
seraphim [82]

Answer:

ΔG° = 1747.523

Explanation:

The parameters mentioned are;

Gibbs Free energy ΔG°

Equilibrium constant Kc

Temperature T = 37 + 273 = 310 (upon conversion to kelvin temperature)

The formular relating all three parameters is given as;

ΔG° =  -RTlnKc

Where; R = rate constant = 8.314 J⋅K−1⋅mol−1

Upon solving;

ΔG° = - 8.314 * 310 * ln(1.97)

ΔG° = 1747.523

6 0
3 years ago
Cuál será el volumen de ácido clorhídrico concentrado, de densidad 1,19g/mL del 38% de ácido en peso, que se necesita para prepa
julsineya [31]

Answer:

Sorry I speak English can't help

7 0
3 years ago
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