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GalinKa [24]
3 years ago
9

Calculate the wavelength of a football (425g) thrown by an NFL quarterback traveling at 50mph

Chemistry
1 answer:
AnnyKZ [126]3 years ago
7 0

Wavelength is 6.976 x 10^ -35 m

Explanation:

In this, we can use De Broglie’s equation. This equation is the relationship between De Broglie’s wavelength, velocity and the mass of a moving object. In this equation, we are using plank's constant which is 6.626 x 10^-34 m^2 kg/s.

We know that one mile per hour is equivalent to 0.447 M/S.

And One gram is equivalent to 10^-3 kg.

De Broglie’s wavelength = λ ( wave length) = Plank’s constant/ Mass x velocity

λ ( wave length) = 6.626 x 10^ -34/ (425 x10^-3) x ( 50 x 0.447)

                                 = 6.626 x 10^ -34/ 0. 425 x 22.35

                                 = 6.626 x 10^ -34/ 9.498

                                 = 6.976 x10^ -35 m

So, the wavelength of the football will be 6.976 x 10^ -35 m

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Answer:

solubility

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<em>hope it helps :)</em>

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What are the main reactants and products in a neutralization reaction?
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Which element has the greatest electronegativity? B C Cl
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22.4 L is the volume of any gas regardless of atmospheric conditions.<br><br> O True<br><br> O False
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8 0
3 years ago
The empirical formula of a compound is CH2O and its molecular weight is 90.09 g/mol. Determine the molecular formula.
Pachacha [2.7K]

Answer : The molecular formula of the compound will be, C_{3}H_{6}O_3

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

As we are given that the empirical formula of a compound is CH_2O and the molar mass of compound is, 90.09 gram/mol.

The empirical mass of CH_2O = 1(12) + 2(1) + 1(16) = 30 g/eq

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n=\frac{90.09}{30}=3

Molecular formula = (CH_2O)_n=(CH_2O)_3=C_{3}H_{6}O_3

Thus, the molecular formula of the compound will be, C_{3}H_{6}O_3

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3 years ago
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