Answer:
(3) Equals the mass of CaO plus the mass of CO₂
Explanation:
The important principle to remember is the Law of Conservation of Mass — the total mass of the reactants must equal the total mass of the products.
Reactants ⟶ products
CaCO₃ ⟶ CaO + CO₂
Mass of CaCO₃ = Mass of CaO + mass of CO₂
C because this is not very deep and towards the surface you are more likely to find solid rocks
Answer:
1.04 moles of AlCl₃
Explanation:
Balanced Equation: 2Al°(s) + 3Cl₂(g) => 2AlCl₃(s)
Approach => convert given data (28 g Al°) to moles. The number of moles AlCl₃ would equal the number of moles aluminum because coefficients for Aluminum and Aluminum Chloride are equal.
moles Al° = (28g)/(27g/mole ) = 1.04 mole Al°
From balanced equation moles AlCl₃ produced equals moles of Al° produced = 1.04 mole AlCl₃ because coefficients of Al° & AlCl₃.
Answer:
Explanation:
Hello!
In this case, since the determination of empirical formulas requires the moles of the constituents, we first need to calculate the moles in the given grams of the listed elements:
Next, we divide each moles by the fewest moles, in this case, those of phosphorous, in order to determine their subscripts in the empirical formula:
Thus, we multiply these subscripts by 5 to get whole numbers:
Best regards!