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Sergio039 [100]
3 years ago
13

Please help me on this question Algebra 1 question

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0
Rational numbers are decimals that either terminate or repeat, and can be written as fractions, in which case A and E are rational
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Guys I am going to run out of points. Help with 19?<br> I don't need an explanation.
nasty-shy [4]

Answer:

A.) 20x + 2y = 500

B.) y-intercept = 250; its meaning is how many boxes of pencils they started with.

C.) x-intercept = 25; How many T-shirts they can sell at most

Step-by-step explanation:

2y - 500 = -20x

20x + 2y - 500 = 0

20x + 2y = 500

y-intercept = 250; its meaning is how many boxes of pencils they started with.

20x + 2y = 500

20(0) + 2y = 500

2y = 500

2y/2 = 500/2

y = 250

x-intercept = 25; How many T-shirts they can sell at most

20x + 2y = 500

20x + 2(0) = 500

20x = 500

20x/20 = 500/20

x = 25

4 0
3 years ago
A set of golf clubs that costs $600 are on sell for 40% off the regular price. What is the sale price of the clubs?
Marysya12 [62]
The answer to your question is $360
6 0
4 years ago
What is the equation of the line that passes through the point (−6,−3) and has a slope of 0?
umka2103 [35]

The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3

The line is passing through the point = (-6,-3)

The slope of the line = 0

The point slope form is

(y-y_1)=m(x-x_1)

Substitute the values in the equation

(y-(-3)) = 0×(x-(-6))

We have to convert this equation the slope intercept form

Slope intercept form is

y = mx + b

Where m is the slope of the line

b is the y intercept

(y-(-3)) = 0×(x-(-6))

y+3 = 0×(x+6)

y+3 = 0

y = -3

Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.

Learn more about slope intercept form here

brainly.com/question/9682526

#SPJ1

8 0
1 year ago
What percent of 500 is 5
shtirl [24]
That my dear friend is... 25
5 0
3 years ago
What is the product of 84,90?
MAVERICK [17]
84•90 is 7,560.

ndheisn
3 0
4 years ago
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