Answer:

Step-by-step explanation:
we know that
The measure of central angle ABC is
radians
so

subtends the complete circle
The area of the shaded sector is the area of a quarter circle
so
The area of a quarter circle is equal to

we have

substitute

Answer:
16.32 N11.38°E km/h
Step-by-step explanation:
16.0∠0° +3.22∠90° ⇒ (x, y) = (3.22, 16.0) ⇒ (r, θ) =
(3.22, 16.0) ⇒ (r, θ) = (√(3.22² +16²), arctan(3.22/16)*) = (16.32, 11.38°)
The woman's velocity is 16.32 km/h in a direction that is 11.38° east of north.
_____
This is her velocity in any stationary frame of reference.
____
* We have used North as the reference for the angle, measured CW.
The question is incomplete. Here is the complete question:
A machine covers 5/8 square foot in 1/4 hour. what is the unit rate?
Answer:
2.5 square feet per hour
Step-by-step explanation:
Given:
Area covered by a machine = 
Time taken to cover the given area = 
Now, unit rate of the first quantity with respect to second quantity is the magnitude of the first quantity being when the second quantity is one unit.
Here, the first quantity is the area covered and the second quantity is the time taken.
So, unit rate is the area covered by the machine in 1 hour.
In order to find that, we use the unitary method and divide the area by the total time taken. Therefore,

Thus, the unit rate is 2.5 square feet per hour.
Answer:
Their welders earn $50,000 annually.
Step-by-step explanation:
Given : 

n = 100

To Find : The ship building association wishes to find out whether their welders earn more or less than $50,000 annually.
Solution :

n = 100
Since n > 30
So we will use z test

Substitute the values


Refer the z table for p value
p value = 0.9599
α= 0.05
Since p value > α
So we accept the null hypothesis .
Hence their welders earn $50,000 annually.
<h3>
Answer: 14s^4 - 7s^2 + 15</h3>
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Work Shown:
(12s^4-6s^2+4s)+(6s^4-4s+27)-(4s^4+s^2+12)
12s^4-6s^2+4s+6s^4-4s+27-4s^4-s^2-12
(12s^4+6s^4-4s^4)+(-6s^2-s^2)+(4s-4s)+(27-12)
14s^4-7s^2+0s+15
14s^4-7s^2+15
Note: don't forget to distribute the negative to every term in the last parenthesis