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vfiekz [6]
2 years ago
6

susan designed a circular pool with a diameter of 24 meters. what is the area of the bottom of the pool?

Mathematics
1 answer:
Gennadij [26K]2 years ago
7 0
Diameter = 24 m

radius = diameter/2 = 24 m / 2 = 12 m

area = pi * r^2 = 3.14 * (12 m)^2 = 3.14 * 144 m^2 = 452.16 m^2
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A 96 foot tree casts a shadow that is 120 feet long. What is the angle of elevation of the sun? Round to the nearest degree.
zysi [14]

Answer:

\alpha \approx 39^{\circ}

Step-by-step explanation:

Let assume that tree grows perpendicular to surface. The statement is geometrically represented in the attachment included below, which resembles a right-angled triangle. Lastly, the angle of elevation of the sun is determined with the help of the following trigonometric relationship:

\tan \alpha = \frac{96\,ft}{120\,ft}

\tan \alpha = \frac{4}{5}

\alpha = \tan^{-1}\left(\frac{4}{5} \right)

\alpha \approx 38.660^{\circ}

\alpha \approx 39^{\circ}

4 0
3 years ago
Multiply the polynomial vertically:<br> 1/2x^2(12x^2 - 4x + 2)
Anna35 [415]

Step-by-step explanation:

= 1/2x^2.12x^2 - 1/2x^2.4x + 1/2x^2.2

= 6x^4 - 2x^2 + x

5 0
2 years ago
Help me with this only number 1
stira [4]

Answer:

25

Step-by-step explanation:

You have is circled plus 25 is 5 and 5 multiplied and 5 is a prime number.

8 0
2 years ago
The y-intercept of the line whose equation is 2x + y = 4 is -2 2 4
Ber [7]

The y intercept is the value of y when x=0.  Substituting we get

y = 4

Answer: 4

8 0
3 years ago
Read 2 more answers
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
2 years ago
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