True or False - Explain the graphs of two different direct variations can be parallel

Mathematics

2 answers:

Montano1993 [528]2 years ago

6 0

False.because u have to do the vlt

Kruka [31]2 years ago

3 0

False because you in comepare and coaiser

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Sean used candle molds, as shown, to make candles that were perfect cylinders and spheres:

BaLLatris [955]

We calculate for the volumes of each of the wax needed for the candles through the equations presented below.

For cylinder:
V = πr²h
where V is volume, r is radius and h is height.

Substituting the known values,

V = (3.14)(3 in)²(6 in)
V = 169.56 in³

For sphere:

V = 4πr³/3
Substituting the known values,
V = 4(3.14)(3 in)³ / 3 = 113.04 in³

The difference between the two volumes,

difference of volumes = 169.56 in³ - 113.04 in³
difference of volumes = 56.52 in³

Thus, the answer to this item is the last choice.

4 0

2 years ago

Please help me this is a post test!

schepotkina [342]

Answer:

I cant see, Camera quaily is bad.

Step-by-step explanation:

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2 years ago

Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevat

morpeh [17]

So, you would 13 + 9 = which is 22 feet and since the angle is 50 degrees, you would multiply 22 x tan(50) to find the height of the streetlamp:22 x tan(50) = 26.21. So, the streetlamp is about 26 feet tall!Hope this helps!

3 0

2 years ago

Can two fractions with the same numerator and different denominators can be equal.

mel-nik [20]

Nope!

They cannot be equal if they have the same numerator but different denominators. they need to be able to reduce into the same number

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2 years ago

HELP WITH THESE QUESTIONS PART 2.

polet [3.4K]

Answer: (a) IV (b) positive (c) $\frac{\pi}{4}$ (d) C (e) $\sqrt{2}$

Step-by-step explanation:

a) $\frac{15\pi}{4}$ - $\frac{8\pi}{4}$ = $\frac{7\pi}{4}$ , which is located in Quadrant IV per the Unit Circle.

b) sec is $\frac{1}{cos}$ . Cos is the x-coordinate. The x-coordinate inQuadrant IV is positive.

c) the reference angle is the angle from $\frac{7\pi}{4}$ to 2π = $\frac{\pi}{4}$

d) since the angle is below the x-axis and the reference angle is $\frac{\pi}{4}$ , then the angle is equal to $-sec(\frac{\pi}{4}$ )

e) sec = $\frac{1}{cos}$ ⇒ sec $\frac{7\pi}{4}$ = $\frac{2}{\sqrt{2} }$ = $\frac{2}{\sqrt{2} }$ $(\frac{\sqrt{2}} {\sqrt{2}})$ = $\frac{2\sqrt{2} }{2}$ = $\sqrt{2}$