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2 years ago

Pls help its not hard i need 100% on this ugh

Mathematics

2 answers:

weeeeeb [17]2 years ago

8 0

The answer is:
b= -3a/4+2

Nookie1986 [14]2 years ago

4 0

Answer. B= -3/4 a + 2

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what expression is equivalent to 2x+9-x+3? show your answer is correct by substituting a value for x.

Sedbober [7]

Collect like terms
(2x-x) + (9+3)

Simplify
x+12

4 0

2 years ago

Whats the contant of proportionality of 46.2 and 107.8

MaRussiya [10]

Answer:

1:2.33

Step-by-step explanation:

Divide 107.8 by 46.2 to get how much 107.8 equals when 46.2 equals 1. you get 1:2.33.

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2 years ago

I need to know if a is right and answers to b and c

xxTIMURxx [149]

Answer:

Your answer is A. my Good sir

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Step-by-step explanation:

3 0

2 years ago

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What's

lakkis [162]

Answer:

$x \leqslant - 21$

Step-by-step explanation:

$5(x + 27) \geqslant 6(x + 26)$ $5x + 135 \geqslant 6x + 156$

$- 21 \geqslant x$

$x \leqslant - 21$

5 0

1 year ago

If cos theta= -8/17 and theta is in quadrant 3, what is cos2 theta and tan2 theta

Karo-lina-s [1.5K]

$\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}\qquad 
\begin{array}{llll}
\textit{now, hypotenuse is always positive}\\
\textit{since it's just the radius}
\end{array}
\\\\\\
thus\qquad cos(\theta)=\cfrac{-8}{17}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}$

since the hypotenuse is just the radius unit, is never negative, so the - in front of 8/17 is likely the numerator's, or the adjacent's side

now, let us use the pythagorean theorem, to find the opposite side, or "b"

$\bf c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite
\end{cases}
\\\\\\
\pm\sqrt{17^2-(-8)^2}=b\implies \pm\sqrt{225}=b\implies \pm 15=b$

so... which is it then? +15 or -15? since the root gives us both, well
angle θ, we know is on the 3rd quadrant, on the 3rd quadrant, both, the adjacent(x) and the opposite(y) sides are negative, that means, -15 = b

so, now we know, a = -8, b = -15, and c = 17
let us plug those fellows in the double-angle identities then

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\
cos(2\theta)=
\begin{cases}
cos^2(\theta)-sin^2(\theta)\\
\boxed{1-2sin^2(\theta)}\\
2cos^2(\theta)-1
\end{cases}
\\ \quad \\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-----------------------------\\\\
cos(2\theta)=1-2sin^2(\theta)\implies cos(2\theta)=1-2\left( \cfrac{-15}{17} \right)^2
\\\\\\
cos(2\theta)=1-\cfrac{450}{289}\implies cos(2\theta)=-\cfrac{161}{289}$

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\left( \frac{-15}{-8} \right)}{1-\left( \frac{-15}{-8} \right)^2}
\\\\\\
tan(2\theta)=\cfrac{\frac{15}{4}}{1-\frac{225}{64}}\implies tan(2\theta)=\cfrac{\frac{15}{4}}{-\frac{161}{64}}
\\\\\\
tan(2\theta)=\cfrac{15}{4}\cdot \cfrac{-64}{161}\implies tan(2\theta)=-\cfrac{240}{161}$

6 0

2 years ago