B+ 11/3= -2
⇒ b= -2 -11/3
⇒ b= -6/3 -11/3
⇒ b= -17/3
⇒ b= -5 2/3
Final answer: b= -5 2/3~
The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Answer:
x = 0 and x = 1
Step-by-step explanation:
Given that,
A football is kicked into the air. The height of the football can be modeled by the equation :
Where
h is the height reached by the ball after x seconds
When it touches the ground, h = 0
So,
So, it will touch the ground at x = 0 and x = 1 seconds.
Answer:
15 units
Step-by-step explanation:
Calculate the distance d using the distance formula
d = 
with (x₁, y₁ ) = (- 1, - 5) and (x₂, y₂ ) = (- 10, 7)
d = 
= 
= 
= 
= 15 units
Answer:
90 cm
Step-by-step explanation:
15 x 6 = 90
