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3 years ago

Simplify 6 - 3/4 - 3x) 0-3X-6 9x + 18 Ox-6

Mathematics

1 answer:

BaLLatris [955]3 years ago

4 0

Answer:

Step-by-step explanation:

21/4-3x

3x-6

9(x+2)

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The wholesale cost of a bicycle is $98.75.

mixer [17]

Answer:

$131.60

Step-by-step explanation:

For the promotion, markup is 33.3% of the selling price.

Now, Selling Price = Cost price + Cost price*Markup

Selling Price = $98.75 + $98.75*33.3%

Selling Price = $98.75 + $32.88375

Selling Price = $131.63375

Selling Price = $131.60

Thus, the selling price of the bicycle after calculating the markup is $131.60.

8 0

2 years ago

Filip is inviting 6 friends to a party. Each friend wants 5 cookies and each box has 8 cookies. How many boxes should Filip get?

Alecsey [184]

Flip should get 4 boxes.

6*5=30
30/8=3.75
round up for 4.

3 0

1 year ago

Chapter 15 probability

denpristay [2]

What do you mean by that?

4 0

3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

2 years ago

Please Help, GodBless

Vedmedyk [2.9K]

Answer:

-3/2

Step-by-step explanation:

The rate of change is the same as slope

7 0

3 years ago