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Luba_88 [7]
2 years ago
13

At the class barbecue, 25 students attended. Of those students, 15 said they wanted hamburgers. What percent wanted hamburgers?

Mathematics
2 answers:
Natali [406]2 years ago
8 0

Answer:

60%

Step-by-step explanation:

Rom4ik [11]2 years ago
5 0

Answer:

60% of the students wanted hamburgers

Step-by-step explanation:

just multiply

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Write an inequality to model the situation. the maximum speed on the highway , x is 55 mi/h
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A maxm speed of 55 mph means that the speed has to be lexx than or equal to 55

x <= 55
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What is the decimal at the bottom of an element on the periodic table​?
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The atomic mass

Step-by-step explanation:

The decimal at the bottom of an element represents how much one atom of that element weighs.

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Convert 0.25 to a fraction in its simplest form​
erik [133]

Answer: 1/4 is the answer

Step-by-step explanation: it is 1/4 because 25/100 = 1/4

may i have brainiest plz i have like 1 or something

8 0
2 years ago
Question partpointssubmissions usedverify that the divergence theorem is true for the vector field f on the region
maxonik [38]
\nabla\cdot\mathbf f(x,y,z)=\dfrac{\partial(3x)}{\partial x}+\dfrac{\partial(xy)}{\partial y}+\dfrac{\partial(5xz)}{\partial z}=3+x+5x=3+6x

By the divergence theorem, the flux across the boundary of the given region \mathcal E is

\displaystyle\iint_{\partial\mathcal E}\mathbf f(x,y,z)\cdot\mathrm d\mathbf S=\iiint_{\mathcal E}\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV
=\displaystyle\int_{z=0}^{z=2}\int_{y=0}^{y=2}\int_{x=0}^{x=2}(3+6x)\,\mathrm dx\,\mathrm dy\,\mathrm dz=72

4 0
3 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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