This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Answer: 3000 multiplied by 0.05
and u get you get the 0.05 by dividing 5 by 100.
Step-by-step explanation:
Answer:
- 3
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - 3x + 9 ← is in slope- intercept form
with slope m = - 3
Parallel lines have equal slopes, thus
y = - 3x + 4 ← is the equation of a parallel line
Answer:
y=-2x-5
Step-by-step explanation:
y-y1=m(x-x1)
y-(-7)=-2(x-1)
y+7=-2x+2
y=-2x+2-7
y=-2x-5
different between A and B
=30-(-30)
=60
position of C from A or B
=(60÷3)×2
=40
possible value of c
=-30+40
=10
possible value of c
=30-40
=-10