The first step would be to isolate a variable (solve for a variable)....so u will have something to sub into the other equation
F: R -> R, f(x) = ax + b;
f(1) = 8 => a + b = 8;
f(2) = 14 => 2a + b = 14 => a = 6 and b =2;
f(3) = 20 => 6*3 + 2 = 20 True;
f(4) = 26 => 4*6 + 2 = 26 True;
then, f:R -> R, f(x) = 6x + 2;
When you derive a function from another using the transformation

you're translating the graph of the parent function f(x) horizontally.
More specifically, you translate the graph k units to the left if k is positive, k units to the right if k in negative.
So, starting from the graph of f(x), you have that the graph of

is the same graph of f(x), but shifted 3 units to the left.
1:5 or 2:10 because if you divide 10 by 2 you get 5 and 2 divided by 2 it is 1
Answer:
(−3b4)2
−12
b−9
=
−3
4
b8
b9
=
−3
4b
Step-by-step explanation: