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poizon [28]
3 years ago
8

The coordinates A(0,0) B(0,4) C(3,4) and D(3,0) are graphed and connected together. What 3 dimensional shape will be created whe

n this shape is rotated about the Y axis?

Mathematics
1 answer:
Anit [1.1K]3 years ago
6 0
All you have to do is rotate the current dots, and bam.

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Assume each figure shown has the same orientation. Which figure is the image of square LMNP after a translation of (x, y) → (x +
creativ13 [48]

<u>Answer-</u>

Figure 4 is the image of square LMNP after a translation of (x, y) → (x + 5, y – 3)

<u>Solution-</u>

The co-ordinates of the vertices are,

L = (-3, 1)

M = (-1, 1)

N = (-1, -1)

P = (-3, -1)

A translation of (x, y) → (x + 5, y – 3) means, the point must be shifted 5 units right and then 3 units down.

After the transformation the new co-ordinates will be,

L = (-3+5, 1-3) = (2, -2)

M = (-1+5, 1-3) = (4, -2)

N = (-1+5, -1-3) = (4, -4)

P = (-3+5, -1-3) = (2, -4)

These are the co-ordinates of the figure no. 4

6 0
3 years ago
Read 2 more answers
Figure out this missing number pattern:\<br> 1,1,2,3,5_,_,_
Mamont248 [21]
What you have here is the fibonacci sequence. 
Each number in the sequence adds itself to the number before it.
1+1 = 2
1+2 = 3
3+2 = 5
5+3 = 8
8+5 = 13
the sequence is 0,1,1,2,3,5,8,13
8 0
2 years ago
HELP ME PLEASE !!!!!!
koban [17]

Answer:

13.08

Step-by-step explanation:

Step 1: find the sum of all numbers

= 104.65

Step 2: divide by how many values there are

=8

Step 3: solve

104.65 ÷ 8 = 13.08125....

Step 4: round to the hundredths place

= about 13.08

5 0
3 years ago
Read 2 more answers
What is the value of f in the equation f+1/6=3/7
kari74 [83]
11/42
The way I got it is because I took 1/6 minus 3/7 to get the answer of f=11/42
4 0
2 years ago
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If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?
melamori03 [73]
\bf \qquad \textit{Compound Interest Earned Amount}&#10;\\\\&#10;A=P\left(1+\frac{r}{n}\right)^{nt}&#10;\quad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &\$4432.37\\&#10;P=\textit{original amount deposited}\to &\$3000\\&#10;r=rate\to r\%\to \frac{r}{100}\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{annually, thus once}&#10;\end{array}\to &1\\&#10;t=years\to &8&#10;\end{cases}

\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8&#10;\\\\\\&#10;\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r&#10;\\\\\\&#10;0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086&#10;\\\\\\&#10;r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}
6 0
3 years ago
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