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Andre45 [30]
3 years ago
9

Find the midpoint between P(-8, -7) and K(11,5).

Mathematics
1 answer:
irakobra [83]3 years ago
6 0

Answer:

M(3/2, -1)

Step-by-step explanation:

(\frac{x_1+y_1}{2},\frac{x_2+y_2}{2})\\ \\(\frac{-8+11}{2},\frac{-7+5}{2})\\\\(\frac{3}{2},\frac{-2}{2})\\\\(\frac{3}{2},-1)

Therefore, the midpoint between P(-8, -7) and K(11,5) is M(3/2, -1)

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-10=xy + z for x Solve for the indicated variable in each literal equation
Aleksandr-060686 [28]
We start with:
-10 = xy + z

When you want to solve for a certain variable, you generally follow pemdas in reverse, so subtract z from both sides first:
-10 - z = xy

And finally, divide both sides by y:
(-10 - z)/y = x

and there we go! sorry for the badly typed equations, I'm on my phone so there's only so much a can do :( hope I helped, and let me know if you have any questions!
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4 years ago
Explain how to determine the
Paladinen [302]

Answer: Compound probability is equal to the probability of the first event multiplied by the probability of the second event

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3 0
3 years ago
Please help (7th grade math)
Illusion [34]

The scatter plot shows the association between the ordered pairs

The two ordered pairs that can be joined to best draw the line of best fit for this scatter plot are (0, 13) and (10, 0)

<h3>How to determine the two best ordered pairs?</h3>

To draw the line of best fit, the line must pass through at least two points such that the number of points on either sides of the line must be equal

See attachment for illustration

From the attached image of the graph, we can see that the line passes through the points (0, 13) and (10, 0), and there are 4 points on either sides

Hence, the two ordered pairs are (0, 13) and (10, 0)

Read more about scatter plots at:

brainly.com/question/2820882

4 0
2 years ago
Read 2 more answers
I need help with this question
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

f(x) = 6x³-x²+4x+5

g(x) = 9x³-1

(f+g)(x) = {6x³-x²+4x+5} + {9x³-1}

open brackets

6x³-x²+4x+5 + 9x³-1

choose like terms

6x³+ 9x³-x²+4x+5 -1

15x³-x²+4x+4= x²(15x-1)+4(x+1)= (x²+4)(x+1)(15x-1)

(f+g)(x)= 15x³-x²+4x+4 =  (x²+4)(x+1)(15x-1)

(f+g)(2) = 15(2)³-(2)²+4(2)+4 = 15(8)-4+8+4 = 120+8 = 128

(f-g)(x) = {6x³-x²+4x+5} - {9x³-1}

open brackets

6x³-x²+4x+5 - 9x³+1

choose like terms

6x³- 9x³-x²+4x+5 +1

-3x³-x²+4x+6= -x²(3x+1)+2(2x+3)= (-x²+2)(3x+1)(2x+3) =  (2-x²)(3x+1)(2x+3)

(f-g)(x) = -3x³-x²+4x+6 = (2-x²)(3x+1)(2x+3)

(f-g)(-3) = -3(-3)³-(-3)²+4(-3)+6 = -3(-3x-3x-3)-(-3x-3)-12+6=-3(-27)-3(9)-12+6= 81-27-12+6 = 54-6= 48

(f-g)(-3) = 48

4 0
3 years ago
Pls help i don’t know how to do this
algol [13]

Answer: \displaystyle\\\frac{2\pi }{3},\ \frac{5\pi }{3}  .

Step-by-step explanation:

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N=2\\\theta=\frac{2\pi }{3}+2\pi \\ \theta=\frac{2\pi +3*2\pi }{3}\\ \theta=\frac{2\pi +6\pi }{3} \\\theta=\frac{8\pi }{3} \\\theta=2\frac{2}{3} \pi \ \ \ \  (\notin0\leq \theta\leq 2\pi).\\

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