complete question:
The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the original number. How do you find the original numeral?
Answer:
The original number is 10a + b = 10 × 3 + 5 = 35
Step-by-step explanation:
Let
the number = ab
a occupies the tens place while b occupies the unit place. Therefore,
10a + b
The sum of the digits of two-digits numeral
a + b = 8..........(i)
If the digits are reversed. The reverse digit will be 10b + a. The new number is 18 greater than the original number.
Therefore,
10b + a = 18 + 10a + b
10b - b + a - 10a = 18
9b - 9a = 18
divide both sides by 9
b - a = 2...............(ii)
a + b = 8..........(i)
b - a = 2...............(ii)
b = 2 + a from equation (ii)
Insert the value of b in equation (i)
a + (2 + a) = 8
2a + 2 = 8
2a = 6
a = 6/2
a = 3
Insert the value of a in equation(ii)
b - 3 = 2
b = 2 + 3
b = 5
The original number is 10a + b = 10 × 3 + 5 = 35
It’s the first answer choice
Hope this helps
Answer:
45°
135°
Step-by-step explanation:
Let the measure of one angle be x
So, measure of its supplementary angle = 3x

Answer: 560
Step-by-step explanation:
There are [20, 22, 24, 26, 28]: 5 even integers for each ten numbers.
The 20's set can be written as 5*20 + (2+4 + 6 + 8) = 5*20 + (20) = 120
The 30's can be written: 5*30 + 20 = 170
40's: 5*40+20 = 220
50's: 5*50+20 = 270
60's: 5*60+20 = 320
Each set is incremented by 50
We want the sets for 20, 30, and 40, plus the number 50.
(120+170+220+50) = 560
You can also do this in Excel (attached). Set the first cell to 20, the next cell below equal to the cell above plus 2. Then draw the second cell down until you've reached 50. Then sum the cells to arrive at 560.