<span>the answer is 59.25 – 8.67 = </span>50.58
Answer:
Let the distance between woman and pole be "x".
From diagram,
In ΔOAB,
tan 18 = 
tan 18 = 
∴ x =
................ (1)
In ΔOBC
tan 14 = 
tan 14 = 
y = x × tan 14 ..............(2)
equating (2) in (1), we get;
x = 
x = 
∵ tan 18 + tan 14 = 0.574
<em>∴ x = 113.2 ft</em>
<em>i.e. The her distance from the pole is 113.2 ft.</em>
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
La fille a mudane guah garcon la homme la femme. 6/9
Answer:
-539.44
Step-by-step explanation: