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3 years ago

Write 45 as a product of prime factors.

1 answer:

7 0

45=9 x 5
=3 x 3 x 5
Break up 45 into factors and that factor into factors until all of the factors are prime.
45=3 x 3 x 5
Hope this helps.

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If f(x) = 2x²+2 and g(x) = x² - 1 ,find (f- g)(x).

mestny [16]

Step-by-step explanation:

(F-g) (X)

= f(x) - g(x)

(2x² + 2 )-(x²-1) =

3x²+3

4 0

3 years ago

In a manufacturing process, a random sample of 36 bolts has a mean length of 3 inches with a standard deviation of .3 inches. Wh

Liula [17]

The 99 percent confidence interval for the true mean length of the bolt is CI = (2.8712, 3.1288)

<h3>How to find the confidence interval?</h3>

Confidence Interval is used to tell us the degree of certainty or uncertainty that is existent in a sampling method.

The general formula for confidence interval is;

CI = x' ± z(s/√n)

where;

x' is sample mean

z is z-score at confidence level

s is sample standard deviation

n is sample size

We are given;

sample size; n = 36

Sample mean; x' = 3 inches

standard deviation; s = 0.3 inches

confidence level = 99%

z at 99% CL = 2.576

Thus;

CI = 3 ± 2.576(0.3/√36)

CI = 3 ± 0.1288

CI = (2.8712, 3.1288)

Read more about Confidence Interval at; brainly.com/question/17097944

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3 0

1 year ago

Trigonometry

quester [9]

Answer:

$\frac{9 + 2 \sqrt{3} }{3} \\$

Step-by-step explanation:

$\cosec(30) + \cosec(60) + \cosec(90) \\ \\ = 2 + \frac{2}{ \sqrt{3} } + 1 \\ \\ = \frac{2 \sqrt{3 } + 2}{ \sqrt{3} } + 1 \\ \\ = \frac{2 \sqrt{3} + 2 + \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} + 2}{ \sqrt{3} } \\ \\ = \frac{3 \sqrt{3} + 2}{ \sqrt{3} } \times \frac{ \sqrt{3} }{ \sqrt{3} } \\ \\ = \frac{9 + 2 \sqrt{3} }{3}$

4 0

3 years ago

Read 2 more answers

What is the value of y in the solution to this system of equations?<br> y=3-2x/2<br> 4x-6y=36

Paul [167]

Answer:

idekqwarwera

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If a sequence is defined recursively by (0)=3 and (n+1)=-f(n)+5 for n≥0, Then f(2) is equal to

lana66690 [7]

Answer:

f(2) = 3

Step-by-step explanation:

We are given:

f(0) = 3

and

f(n+1) = -f(n) + 5

We have to find the value of f(2). In order to find f(2) we first have to find f(1)

f(n + 1) = - f(n) + 5

Using n = 0, we get:

f(0 + 1) = - f(0) + 5

f(1) = -f(0) + 5 Using the value of f(0), we get

f(1) = -3 + 5 = 2

Now using n = 1 in the function, we get:

f(1 + 1) = - f(1) + 5 Using the value of f(1), we get

f(2) = -2+ 5

f(2) = 3

Thus the value of f(2) will be 3

6 0

3 years ago