Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
Mean: 5.5555555555556
Median: 6
Mode: 6
Step-by-step explanation:
Answer:
26 units^2
Step-by-step explanation:
the area of a kite is (d1 * d2)/2
d1 = 2 + 2 = 4
d2 = 6 + 7 = 13
4 * 13 = 52
52 / 6 = 26
26 units^2 is your answer
Answer:
28 deg
Step-by-step explanation:
Reference angle is the smallest angle formed by the terminal ray, x-axis, and origin. So at 180 you are on the x-axis so just for this question you have to do 180-152=28.
The reference angle should be a positive between 0 and 90 degrees.
Answer:
x = 16 y= 16√3
Step-by-step explanation:
we know that a angle is 60 degrees. Thanks to this information we can say that x is half the hypothenuse, so is value is 16.
y can be express as √3/2 x 32 = 16√3
