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umka2103 [35]
3 years ago
8

1+tan²A/1+cot²A find its value​

Mathematics
1 answer:
butalik [34]3 years ago
3 0

Answer:

tan²A  

Step-by-step explanation:

1+tan²A/1+cot²A      Simplify 1+tan²A first

sec²A/1+cot²A         Now simplify 1+cot²A

sec²A/csc²A            Simplify sec²A and csc²A    

\frac{1}{cosA}/\frac{1}{sinA}                   Simplify the fraction

sin²A/cos²A = tan²A  

If this answer is correct, please make me Brainliest!

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the length of a soccer pitch is 20 m less than twice its width. the area of the pitch is 6000m^2. find its dimensions.
Setler79 [48]
X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:

x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60

x=60
2x-20=2(60)-20=120-20=100

Solution: the length is 100 m, and the width is 60 m.

To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.


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D is the midpoint of CE. C has coordinates
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Step-by-step explanation:

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