Answer:
Step-by-step explanation:
Remark
What you don't know and what makes the problem confusing, is that where to the given arcs start and end. So I am going to say that both arcs start from E and 119 ends at D, and 174 ends at F which means that the arc FD is not known, but it is not hard to find.
The total number of degrees from beginning to end is 360 degrees. The formula for finding FD is
Formula
FD = 360 - (174 - 119)
The formula for x is (ED - FD)/2
Solution
Arc FD = 360 - (174 - 119)
Arc FD = 67
So x = (119 - 67) / 2
x = 52 /2
x = 26
The correct answer is 10.
In order to evaluate any composite function, you need to first put the value in for the inside function. In this case f(x) is on the inside along with the number 3. So, we input 3 in for x in f(x).
f(x) = 2x + 1
f(3) = 2(3) + 1
f(3) = 6 + 1
f(3) = 7
Now that we have the value of f(3), we can stick the answer in for the outside function, which is g(x).
g(x) = (3x - 1)/2
g(7) = (3(7) - 1)/ 2
g(7) = (21 - 1)/2
g(7) = 20/2
g(f(3)) = 10
Answer:
The quadrilateral is Parallelogram.
Step-by-step explanation:
A quadrilateral is a four-sided regular polygon.
A parallelogram is a quadrilateral.
The opposite sides of a parallelogram are parallel and equal in length.
The opposite angles of a parallelogram are also equal.
In this case the quadrilateral is defined as follows:
- two angles that each measure 60°
- two angles that each measure 120°
- Only two of the sides have a length of 3.2 inches.
Consider the quadrilateral ABCD below.
The quadrilateral ABCD is Parallelogram.
Answer:

Step-by-step explanation:
All the relations are not functions. We can determine ( identify ) whether a relation is function or not by drawing a vertical line intersecting the graph of the relation. This is called vertical line test.
- If the vertical line intersects the graph of a relation at one point , the relation is a function .
- If it cuts at more than one point , it is not a function. It means that if there are more points of the graph of a relation of a vertical line , same first component ( pre - image ) has more images ( second component ) which is not the function by definition.
--------------------------------------------------
Let's check all of the options :
☐ Option A :
- The vertical line cuts the graph at two points. So , the graph does not represent a function.
☐ Option B
- No! This is also not a function as the vertical line cuts the graph at two points.
☐ Option C
- Nah! This too can't be called a function as the vertical line cuts the graph at two points.
☑ Option D
- Yep! The vertical line cuts the graph at one point. Thus , the graph represents a function.
Yayy!! We found our answer. It's ' Option D '.
Hope I helped ! ツ
Have a wonderful day / night ! ♡
▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation: