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soldi70 [24.7K]
3 years ago
12

Solve log x=2. A. 2 B. 20 C. 100 D. 1,000

Mathematics
2 answers:
Ber [7]3 years ago
5 0

Answer:

100

Step-by-step explanation:

Grace [21]3 years ago
5 0

Answer:

C. 100

Step-by-step explanation:

㏒ x = 2

㏒10 (x) = 2      (b^y = x), in this case b = 10 , y = 2

so

10^2 = x

100 = x

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Which construction is the Perpendicular Bisector Construction?
Leni [432]

Answer:

Step-by-step explanation:

This construction shows how to draw the perpendicular bisector of a given line segment with compass and straightedge or ruler. This both bisects the segment (divides it into two equal parts, and is perpendicular to it. It finds the midpoint of the given line segment.

6 0
4 years ago
(d)
mash [69]

Answer: The 4 answers are x=18, x=3, x=48, x=81 1/2.

Step-by-step explanation: Isolate the variable by dividing by each side by factors that don't contain the variable.

6 0
3 years ago
Determine whether the given linear equations are parallel, perpendicular, or neither.
ladessa [460]

Answer:

A. Perpendicular

Step-by-step explanation:

Lines are perpendicular if their slopes are opposite reciprocals of each other. Opposite, meaning if positive, the other slope is negative, and if negative, the other slope is positive. Reciprocal meaning, the number is flipped upside down, turning fractions into whole numbers and vice versa.

1/9  

-1/9

-9

The slopes are perpendicular

4 0
3 years ago
A and B are two similar shapes the area of shape A is 200cm2 calculate the area of shape B
barxatty [35]

Answer:

Area of shape B = 312.5 cm²

Step-by-step explanation:

Ratio of Area of A : Area of B = 12² : 15²

Given that area of A is 200 cm², let the area of shape B = x

Therefore:

200:x = 12²:15²

200/x = 144/225

Cross multiply

144x = 200*225

144x = 45,000

x = 45,000/144

x = 312.5 cm²

Area of shape B = 312.5 cm²

5 0
3 years ago
The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle.
romanna [79]
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate

cot (theta) = -3/5 / y

y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5

Third quadrant => y = -4/5

=> cot (theta) = (-3/5) / (-4/5) = 3/4
7 0
3 years ago
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