Answer:
13 sheep, 19 chicken
Step-by-step explanation:
You can start to solve this problem by assigning variables. First, let's assign the number of sheep there are as 
and the number of chickens there are as 
.
Because each sheep has 4 legs, the number of legs for each sheep would be 
. Similarly, because each chicken has 2 legs, the number of legs for each chicken would be 
. Each animal would have 1 head, so the number of heads would just be and . Because the number of legs in total are 90, 
. Because the number of heads in total are 32, 
There is now a system of equations with two unknown variables and two equations. There are many ways to solve this, but for me, the easiest would be elimination. First, I would double the second equation, 
. Then, I would subtract that from the first equation, eliminating . 
. Solving for x gives 13. We can then plug that value into the second equation, making y be 
. This means that 
and 
, meaning that there are 13 sheep and 19 chicken.
Y varies x
Invite the constant
y = kx
Kx/x = y/x
K = y/x
Slot in the values
K = 35/140
= 1/4 or 0.25
What is the value of y when x=70
y=kx
y = 35/140 x 70/1
y = 35/2
y = 17 1/2 or 17.5
Eleven subtract nine is two; eight adding three is eleven (2,11)
Answer:
12
Step-by-step explanation:
20-6=14 (Distance between points) then 14*3/7=6.
3/7 of the distance from A=6 to B=20 is 6. Thus, we find the point that is
3/7 of the distance from A=6 to B=20 by adding 6 to 6.
6+6= 12
Therefore, the point that is
3/7 from A=6 to B=20 is 12.
