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Zinaida [17]
3 years ago
12

Suppose that your boss must choose three employees in your office to attend a conference in Jamaica. Because all 17 of you want

to go, he decides that the only fair way is to draw names out of a hat. What is the probability that you, Anna, and Kevin are chosen? Enter a fraction or round your answer to 4 decimal places, if necessary.
Mathematics
1 answer:
Pani-rosa [81]3 years ago
5 0

Answer:

P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}

Step-by-step explanation:

Given

Total\ Employees = 17

To\ Select = 3

Required

Determine the probability of selecting You, Anna and Kevin

Assuming the selection process is fair;

Each employee has a probability of;

Probability = \frac{1}{17}

So:

P(You\ n\ Anna\ n\ Kevin) = P(You) * P(Anna) * P(Kevin)

P(You\ n\ Anna\ n\ Kevin) = \frac{1}{17} * \frac{1}{17} * \frac{1}{17}

P(You\ n\ Anna\ n\ Kevin) = \frac{1}{4913}

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