Given:
3, -2
1, 2
-1, -4
-1, 2
The format is (x,y)
The domain is all the x-values while range is all the y-values.
domain: (3,1, -1,-1) 2nd option given.
Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- There are 12 bulbs, hence N = 12.
- 3 are defective, hence k = 3.
The third defective bulb is the fifth bulb if:
- Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
- The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.
Hence:


0.2182 x 1/8 = 0.0273.
0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
Answer:
27 %
Step-by-step explanation:
Given that Sheila predicts that 480 people will attendthe fall concert and There was an actual total of 350 people who attended the fall concert.
We know that
Percent error = 
Percent error = 
Percent error = 27 %
<span>t – (–16.5) = –13.4
t + 16.5 = -13.4
t = (-13.4) + (-16.5)
t = -29.9
Anser is A. t = -29.9</span>