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nirvana33 [79]
3 years ago
5

Help me with this math question

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0

Answer:

its a or c

Step-by-step explanation:

ik but you figer it out

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Using technology, we found that Juan’s investment account can be modeled by the function, c(x)=3x2-2x+10, in thousands of dollar
irakobra [83]
The function is c(x)=3 x^{2} -2x+10

Initial investment is given when x=0, so substituting this into c(x) we have

c(0)=3 (0)^{2}-2(0)+10

c(0)=10

Hence, correct answer is B $10
4 0
4 years ago
Read 2 more answers
Which number line shows the solution set for |m| = 4
Margaret [11]

Answer:

Last choice that shows points on +4 and -4 is the correct graph.

Step-by-step explanation:

We have been given equation |m|=4. Now we need to find out which of the given number lines shows the corret solution set for |m|=4.

We know that |x|=a can be broken into two parts as:

x=+a and x=-a

Same way we can break |m|=4 into two parts as:

m=+4 and m=-4

Hence last choice that shows points on +4 and -4 is the correct graph.

4 0
3 years ago
How many committees of 4 boys and 3 girls<br> can be formed from a class of 6 boys and 7<br> girls?
VLD [36.1K]

Answer:

525

Step-by-step explanation:

This is a question involving combinatorics

The number of ways of choosing a subset k from a set of n elements is given by {n \choose k} which evaluates to \frac{n!}{k!(n-k)!}

n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1

For example,

4! = 4 x 3 x 2 x 1 = 24

3! = 3 x 2 x 1 = 6

Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is

{6 \choose 4} = \frac{6!}{4!(6-4)!} = \frac{6!}{4!2!}

Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1  is nothing but 4!

So the numerator can be re-written as 6 x 5 x (4!)

We can rewrite the expression \frac{6!}{4!2!} \text{ as } \frac{6.5.4!}{4!2!}

Cancelling 4! from both numerator and denominator gives us the result

as  (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys

For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by

{7 \choose 3} = \frac{7!}{3!(7-3)!} = \frac{7!}{3!4!}

This works out to (7 x 6 x 5 )/(3 x 2 x 1)  (using the same logic as for the boys computation)

= 210/6 = 35

So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525

8 0
2 years ago
When 4x+8y = 24 and y=5, what's the value of x?
ankoles [38]

Answer:

x=10

hope that help!!!!

6 0
3 years ago
Sun estimated the quotient of –23.514 and –3.98 by rounding each to the nearest integer. Which equation shows the correct estima
Aleksandr [31]
-23.514 / -3.98
round to the nearest integer
-24 / -4 = 6
6 0
3 years ago
Read 2 more answers
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